在MySQL中选择不包含特定列的表格

Question

我试图选择没有名为'unique'的列的所有表格。我可以选择有它使用的所有表：

SELECT DISTINCT TABLE_NAME 
FROM INFORMATION_SCHEMA.COLUMNS 
WHERE COLUMN_NAME = 'unique' 
AND TABLE_SCHEMA ='database'; 

有一个简单的方法来修改SELECT语句，因此列出了没有该列的所有表？这看起来很简单，但我无法弄清楚，并且无法在论坛上找到答案。

感谢

Answer 1

select 
t.* 
from INFORMATION_SCHEMA.TABLES as t 
    left join INFORMATION_SCHEMA.COLUMNS as c 
    on c.TABLE_NAME = t.TABLE_NAME 
    and c.TABLE_SCHEMA = t.TABLE_SCHEMA 
    and c.COLUMN_NAME = 'unique' 
where c.COLUMN_NAME is null 
and t.TABLE_SCHEMA = 'database' 

Answer 2

SELECT TABLE_NAME 
FROM INFORMATION_SCHEMA.TABLES 
WHERE TABLE_NAME NOT IN (
SELECT DISTINCT TABLE_NAME 
FROM INFORMATION_SCHEMA.COLUMNS 
WHERE COLUMN_NAME = 'unique' 
AND TABLE_SCHEMA ='database') 

Answer 3

一个简单的反转：

SELECT TABLE_NAME 
FROM INFORMATION_SCHEMA.TABLES 
WHERE TABLE_NAME NOT IN 

(SELECT DISTINCT TABLE_NAME 
FROM INFORMATION_SCHEMA.COLUMNS 
WHERE COLUMN_NAME = 'unique' 
AND TABLE_SCHEMA ='database'); 

Answer 4

上述查询工作，如果只有一个数据库服务器中存在。否则，其他数据库中的表格也将被列出。考虑这个从特定数据库中挑选表格的简化版本。总而言之，这是一个伟大的亮点！

SELECT DISTINCT TABLE_NAME 
FROM INFORMATION_SCHEMA.TABLES 
WHERE TABLE_SCHEMA = 'DATABASE_NAME' 
AND TABLE_NAME NOT IN (SELECT DISTINCT TABLE_NAME 
          FROM INFORMATION_SCHEMA.COLUMNS 
          WHERE COLUMN_NAME = 'FIELD_NAME' 
          AND TABLE_SCHEMA ='DATABASE_NAME');