正则表达式来改变一个字符串，但不是字符串+ string2

Question

我有一个大文件，其中包含localhost和localhost：portnumber（端口号不是constant.it可以是4070,8080,9090）的几行。我想将所有localhost或localhost：portnumber改为localhost：4080.但我不想改变localhost：4080.Simple search and replace（localhost to localhost：4080）will localhost：portnumber to localhost：4080：portnumber.Any的方式在记事本++与regex.Preferbly为此

例如输入：

https://localhost/subservice1 
https://localhost:4080/subservice1 
https://localhost:1090/subservice1 
https://localhost/subservice2 

输出应该是

https://localhost:4080/subservice1 
https://localhost:4080/subservice1 
https://localhost:4080/subservice1 
https://localhost:4080/subservice2 

Answer 1

这应该工作

REGEXP：对于Python和记事本++

(?:.*)(?:\blocalhost\/|localhost:4080\/)(.*) 

REPLACE：

https://localhost:4080/$1 

Python代码：

# coding=utf8 
# the above tag defines encoding for this document and is for Python 2.x compatibility 

import re 

regex = r"(?:.*)(?:\blocalhost\/|localhost:4080\/)(.*)" 

test_str = ("https://localhost/subservice1 \n" 
    "https://localhost:4080/subservice1 \n" 
    "https://localhost/subservice1 \n" 
    "https://localhost/subservice2") 

subst = "https://localhost:4080/$1" 

# You can manually specify the number of replacements by changing the 4th argument 
result = re.sub(regex, subst, test_str, 0, re.MULTILINE) 

if result: 
    print (result) 

# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution. 

REGEXP：

INPUT：

https://localhost/subservice1 
https://localhost:4080/subservice1 
https://localhost/subservice1 
https://localhost/subservice2 

OUTPUT：

https://localhost:4080/subservice1 
https://localhost:4080/subservice1 
https://localhost:4080/subservice1 
https://localhost:4080/subservice2 

参见：https://regex101.com/r/kbPHd6/1

尝试Python代码：http://ideone.com/yNoYzv

如果我帮助ü，标志着我为正确答案和投票了。

说明：

(?: Non-capturing group. Groups multiple tokens together without creating a capture group. 
. Dot. Matches any character except line breaks. 
* Star. Match 0 or more of the preceding token. 
) 
(?: Non-capturing group. Groups multiple tokens together without creating a capture group. 
\b Word boundary. Matches a word boundary position such as whitespace, punctuation, or the start/end of the string. 
l Character. Matches a "l" character (char code 108). 
o Character. Matches a "o" character (char code 111). 
c Character. Matches a "c" character (char code 99). 
a Character. Matches a "a" character (char code 97). 
l Character. Matches a "l" character (char code 108). 
h Character. Matches a "h" character (char code 104). 
o Character. Matches a "o" character (char code 111). 
s Character. Matches a "s" character (char code 115). 
t Character. Matches a "t" character (char code 116). 
\/ Escaped character. Matches a "/" character (char code 47). 
| Alternation. Acts like a boolean OR. Matches the expression before or after the |. 
l Character. Matches a "l" character (char code 108). 
o Character. Matches a "o" character (char code 111). 
c Character. Matches a "c" character (char code 99). 
a Character. Matches a "a" character (char code 97). 
l Character. Matches a "l" character (char code 108). 
h Character. Matches a "h" character (char code 104). 
o Character. Matches a "o" character (char code 111). 
s Character. Matches a "s" character (char code 115). 
t Character. Matches a "t" character (char code 116). 
: Character. Matches a ":" character (char code 58). 
4 Character. Matches a "4" character (char code 52). 
0 Character. Matches a "0" character (char code 48). 
8 Character. Matches a "8" character (char code 56). 
0 Character. Matches a "0" character (char code 48). 
\/ Escaped character. Matches a "/" character (char code 47). 
) 
(Capturing group #1. Groups multiple tokens together and creates a capture group for extracting a substring or using a backreference. 
. Dot. Matches any character except line breaks. 
* Star. Match 0 or more of the preceding token. 
) 

Answer 2

更换://localhost/ 与://localhost:4080/

Answer 3

import re 

text = [ 
    "https://localhost/subservice1", 
    "https://localhost:4080/subservice1", 
    "https://localhost/subservice1", 
    "https://localhost/subservice2" 
] 

regex = r'localhost/' 
for x in text: 
    result = re.sub(regex, "localhost:4080/", x) 
    print(result)