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我想删除一个数据帧与NA元素的行通过执行以下操作:R:为什么我不能在数据框中删除NA元素的行?
cleaned_data <- data[complete.cases(data),]
不过,我仍然没有得到任何行相同的数据帧被删除。我正在运行OS X 10.10.3的3.2.1 R版本。下面是数据:
> dput(data)
structure(list(`1` = structure(c(1L, 1L, 6L, 3L, 3L), .Label = c("1",
"2", "3", "4", "5", "NA"), class = "factor"), `2` = structure(c(5L,
5L, 7L, 2L, 2L), .Label = c("1", "2", "3", "4", "5", "6", "NA"
), class = "factor"), `3` = structure(c(34L, 46L, 66L, 51L, 28L
), .Label = c("0", "1", "10", "100", "105", "11", "110", "112",
"12", "120", "14", "15", "16", "168", "18", "2", "20", "200",
"21", "22", "24", "25", "26", "27", "28", "29", "3", "30", "31",
"32", "35", "36", "4", "40", "41", "42", "42099", "42131", "42134",
"42197", "42292", "45", "48", "49", "5", "50", "54", "55", "56",
"6", "60", "64", "65", "7", "70", "72", "75", "77", "8", "80",
"82", "84", "85", "9", "90", "NA"), class = "factor"), `4` = structure(c(1L,
2L, 1L, 2L, 1L), .Label = c("0", "1", "NA"), class = "factor"),
`5` = structure(c(1L, 1L, 1L, 1L, 1L), .Label = c("0", "1",
"NA"), class = "factor"), `6` = structure(c(1L, 2L, 1L, 1L,
1L), .Label = c("0", "1", "NA"), class = "factor"), `7` = structure(c(2L,
2L, 1L, 1L, 1L), .Label = c("0", "1", "NA"), class = "factor"),
`8` = structure(c(1L, 1L, 1L, 1L, 1L), .Label = c("0", "1",
"NA"), class = "factor"), `9` = structure(c(1L, 1L, 1L, 1L,
2L), .Label = c("0", "1", "NA"), class = "factor")), .Names = c("1",
"2", "3", "4", "5", "6", "7", "8", "9"), row.names = c(NA, 5L
), class = "data.frame")
我认为那些不是'NA's。它们是恰好具有“NA”作为其内容的字符串。 'complete.cases(data)'全部是'TRUE'。 –
true,'sum(is.na(data))'给出0.如果用“真”NA替换字符NA,代码将起作用 – mts
我强烈建议退后一步并检查数据读取过程,因为它看起来像'read。 xxx'没有'na.strings =“NA”'。 – Marek