转换编码阵列的字符串转换成对象

所以即时得到此数组中的从与对象的所有坐标，所述服务器的字符串的形式如下所示：转换编码阵列的字符串转换成对象

"[[[-0.340254,51.605946],[-0.340278,51.605685],[-0.339718,51.604400], 
[-0.339280,51.603746],[-0.338915,51.603454],[-0.338657,51.603018], 
[-0.338427,51.601810],[-0.338518,51.600885],[-0.337471,51.599908], 
[-0.337378,51.599682],[-0.337456,51.599116],[-0.336860,51.597669], 
[-0.335843,51.597043],[-0.335635,51.596816],[-0.335112,51.595720], 
[-0.335232,51.594400],[-0.335057,51.593273],[-0.334827,51.592847], 
[-0.333187,51.591889],[-0.333236,51.590945],[-0.332894,51.590446], 
[-0.332727,51.589868],[-0.332791,51.589320],[-0.332638,51.589156], 
[-0.332028,51.587295],[-0.332326,51.585438],[-0.332243,51.585365], 
[-0.332292,51.585186],[-0.331651,51.582991],[-0.333713,51.581096], 
[-0.334020,51.580570],[-0.334055,51.580013],[-0.337963,51.580123], 
[-0.340047,51.579954],[-0.341778,51.579979],[-0.341883,51.579881]]]"

如何将我转换为数组此？提前谢谢！

，所以我想它的形式[双]

let objects = [[[-0.340254,51.605946],[-0.340278,51.605685],[-0.339718,51.604400], 
[-0.339280,51.603746],[-0.338915,51.603454],[-0.338657,51.603018], 
[-0.338427,51.601810],[-0.338518,51.600885],[-0.337471,51.599908], 
[-0.337378,51.599682],[-0.337456,51.599116],[-0.336860,51.597669], 
[-0.335843,51.597043],[-0.335635,51.596816],[-0.335112,51.595720], 
[-0.335232,51.594400],[-0.335057,51.593273],[-0.334827,51.592847], 
[-0.333187,51.591889],[-0.333236,51.590945],[-0.332894,51.590446], 
[-0.332727,51.589868],[-0.332791,51.589320],[-0.332638,51.589156], 
[-0.332028,51.587295],[-0.332326,51.585438],[-0.332243,51.585365], 
[-0.332292,51.585186],[-0.331651,51.582991],[-0.333713,51.581096], 
[-0.334020,51.580570],[-0.334055,51.580013],[-0.337963,51.580123], 
[-0.340047,51.579954],[-0.341778,51.579979],[-0.341883,51.579881]]]

所以如果我是做objects[0][0]它应该返回[-0.340254,51.605946]

func convert(s: String) -> [[[Double]]]{ 

do{ 

    let array = try NSJSONSerialization.JSONObjectWithData(s.dataUsingEncoding(NSUTF8StringEncoding)!, options: []) as? [[[Double]]] 
    return array! 

}catch{ 

} 
return [[[]]]

}

来源

2016-08-07 Minhal Khan

这是一个数组。向我们举个例子，你想让它看起来像 – quelquecosa

其字符串的语音标记 –

请不要在你的问题中包括答案。如果答案解决了您的问题，请将答案标记为已接受;如果您自己解决了问题，您也可以*发布自己的答案。谢谢。 – Moritz

您只需一个JSON响应3D数组。我装你的串入斯威夫特REPL，并能够分析它，像这样：

import Foundation 

let s = /* your string */ 
let array = NSJSONSerialization.JSONObjectWithData(s.dataUsingEncoding(NSUTF8StringEncoding)!, options: []) as? [[[Double]]]

输出

$R3: [[[Double]]]? = 1 value { 
    [0] = 36 values { 
...

代码示例

func convert(s: String) -> [[[Double]]] { 

    if let data = s.dataUsingEncoding(NSUTF8StringEncoding), 
     let object = try? NSJSONSerialization.JSONObjectWithData(data, options: []), 
     let array = object as? [[[Double]]] 
    { 
     return array 
    } 

    return [[[]]] 
}

来源

2016-08-07 16:04:04 Mazyod

即时新闻，所以我从来没有使用过警卫？或尝试？任何帮助，将不胜感激！ :) –

@MinhalKhan你需要发布更多的代码，所以我可以使用该上下文来示范 – Mazyod

刚刚添加了我试过 –

转换编码阵列的字符串转换成对象

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