Unalignable布尔系列键的类型（DF [DF [DF）

Question

我有一个DF和条件DF [DF [ 'EmployeeName'] == 'JOSEPH德里斯科尔']给出以下输出enter image description here

而当我输入这个df，可以[DF [ 'EmployeeName'] == 'JOSEPH德里斯科尔'] [ 'BasePay']> 140000
它给出这样

24真

名称的输出：BasePay，D型：布尔

现在我不能ø像这样

DF [DF [DF [ 'EmployeeName'] == 'JOSEPH德里斯科尔'] [ 'BasePay']> 140000]

并期望输出与上述图像相同??

Answer 1

你需要boolean indexing或query与布尔由|（or）创建&（and）或（not）面具，~：

df1 = df[(df['EmployeeName'] == 'JOSEPH DRISCOLL') & (df['BasePay'] > 140000)] 

或者：

df1 = df.query("EmployeeName == 'JOSEPH DRISCOLL' & BasePay > 140000") 

样品：

df = pd.DataFrame({'EmployeeName':['JOSEPH DRISCOLL','q'],'BasePay':[1000000,10]}) 
print (df) 
    BasePay  EmployeeName 
0 1000000 JOSEPH DRISCOLL 
1  10    q 

print ((df['EmployeeName'] == 'JOSEPH DRISCOLL') & (df['BasePay'] > 140000)) 
0  True 
1 False 
dtype: bool 

df1 = df[(df['EmployeeName'] == 'JOSEPH DRISCOLL') & (df['BasePay'] > 140000)] 
print (df1) 
    BasePay  EmployeeName 
0 1000000 JOSEPH DRISCOLL 

df1 = df.query("EmployeeName == 'JOSEPH DRISCOLL' & BasePay > 140000") 
print (df1) 
    BasePay  EmployeeName 
0 1000000 JOSEPH DRISCOLL