迭代与C++

Question

2D矢量它已经多年我没有使用C/C++，我想复习基础知识，我有一个问题要重复上一个三维矢量：

#include  <string> 
#include  <vector> 
#include  <iterator> 

int            main() { 
    std::vector< std::vector<std::string> >  container; 
    std::vector<std::string>      table; 
    std::string         line; 

    for (int container_it = 0; container_it < 2; container_it++) { 
    for (int table_it = 0; table_it < 5 ; table_it++) { 
     line = "TEST"; 
     table.push_back(line); 
    } 
    container.push_back(table); 
    } 


    for (std::vector< std::vector<std::string> >::iterator container_it = container.begin(); container_it != container.end(); container_it++) 
    for (std::vector<std::string>::iterator it = (*container_it)->begin(); it != (*container_it)->end(); it++) 
     std::cout << *it << std::endl; 
} 

我得到的错误：

base operand of ‘->’ has non-pointer type ‘std::vector<std::basic_string<char> >’ 
base operand of ‘->’ has non-pointer type ‘std::vector<std::basic_string<char> >’ 

Answer 1

我与克里斯同意，我只在这里看到2个维度和代码有一些语法错误，但它看起来像这样一行：

for (std::vector<std::string>::iterator it = (*container_it)->begin(); it != (*container_it)->end(); it++) 

应该是：

for (std::vector<std::string>::iterator it = (*container_it).begin(); it != (*container_it).end(); it++) 

或者更简单地说：

for (std::vector<std::string>::iterator it = container_it->begin(); it != container_it->end(); it++)