通过pyCurl上传文件

Question

我想将下面的curl代码转换成pycurl。我不想使用请求。我需要使用pycurl，因为请求在我的旧Python版本中并不完全工作。

curl 
-X POST 
-H "Accept-Language: en" 
-F "images_file=@fruitbowl.jpg" 
-F "parameters=@myparams.json" 
"https://gateway-a.watsonplatform.net/visual-recognition/api/v3/classify?api_key={api-key}&version=2016-05-20" 

有人可以告诉我如何在PyCurl中写出来吗？

Answer 1

import pycurl 
c = pycurl.Curl() 
c.setopt(c.URL, 'https://gateway-a.watsonplatform.net/visual-recognition/api/v3/classify?api_key={api-key}&version=2016-05-20') 
c.setopt(c.POST, 1) 
c.setopt(c.HTTPPOST, [("images_file", (c.FORM_FILE, "fruitbowl.jpg"))]) 
c.setopt(c.HTTPPOST, [("parameters", (c.FORM_FILE, "myparams.json"))]) 
c.setopt(pycurl.HTTPHEADER, ['Accept-Language: en']) 
c.perform() 
c.close()