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谁可以帮助给出一个shell脚本示例来显示$*
和[email protected]
之间的区别?
以下是我的脚本,但它无法分辨。任何人都可以举一个好榜样?
$ cat internalVar.sh
#!/bin/bash
# internalVar.sh var1 var2
echo "\$? = " $?
export IFS="_"
echo "\[email protected] = " [email protected] " == several parameters?"
j=1
for i in [email protected]
do
echo "var $j = $i"
j=$((j+1))
done
echo "\$* = " $* " == a single string"
j=1
for i in $*
do
echo "var $j = $i"
j=$((j+1))
done
echo "\$# = " $#
echo "\$0 = " $0
echo "\$$ = " $$
$ export IFS="c"
[$ ./internalVar.sh par1 "par meter 2" par3
$? = 0
[email protected] = par1 par meter 2 par3 == several parameters?
var 1 = par1
var 2 = par meter 2
var 3 = par3
$* = par1 par meter 2 par3 == a single string
var 1 = par1
var 2 = par meter 2
var 3 = par3
$# = 3
$0 = ./internalVar.sh
$$ = 4638
您的脚本无法区分它的差异,因为它没有使用适当的引号。如果没有正确引用,那么**就没有区别(并且会有很多错误)。 –
@CharlesDuffy Duh,当然有重复。我一定以为“这不是问'var = val',它一定是新的;) –
谢谢你们,我明白了。 –