我正在提交一个html表单到一个MySQL数据库与jQuery .ajax。当我提交表单时(所有字段都经过验证),数据将作为新记录插入到数据库中,但成功函数不会运行。jQuery Ajax表单提交无视'成功'功能,重新加载页面
*这是在谷歌地图信息窗口都正在发生,但我不知道这是相关的。
HTML:
<div id="formDiv">
<form name="htmlForm" id="htmlForm">
<p id="contactP">
<label for="contact">Email:</label>
<input type="text" name="contact" id="contact"/> <br/>
</p>
<p id="phoneP">
<label for="phone">Phone:</label>
<input type="text" name="phone" id="phone"/> <br/>
</p>
<p id="datepickerP">
<label for="datepicker">Date:</label>
<input type="text" name="date" id="datepicker"/> <br/>
</p>
<p id="latP">
<label for="lat">Latitude:</label>
<input type="text" name="lat" id="lat" class="location"/> <br/>
</p>
<p id="lngP">
<label for="lng">Longitude:</label>
<input type="text" name="lng" id="lng" class="location"/> <br/>
</p>
<p id="descP">
<label for="desc" id="dos">Description of Sighting:</label> <br/>
<textarea name="desc" id="desc"></textarea><br/>
</p>
<input type="submit" class="button" id="submitBtn" value="Post Sighting!" onClick="postSighting();"/>
</div>
的Javascript/jQuery的:
function postSighting() {
// jQuery Validate
$('#htmlForm').validate({
rules: {
contact: {required:true, email:true},
phone: {required:true},
date: {required:true, date:true},
lat: {required:true},
lng: {required:true},
desc: {required:true},
},
messages: {
desc: 'Please be descriptive!'
},
errorPlacement: function(error, element) {
error.appendTo($('#' + element.attr('id') + 'P'));
return false;
};
});
//jQuery ajax form submit
var contact = $('input#contact').val(),
phone = $('input#phone').val(),
date = $('input#datepicker').val(),
lat = $('input#lat').val(),
lng = $('input#lng').val(),
desc = $('textarea#desc').val();
var dataString = "contact=" + contact + '&phone=' + phone + "&date=" + date + "&lat=" + lat + "&lng=" + lng + "&desc=" + desc;
$.ajax({
type: "POST",
url: "Includes/test.php",
data: dataString,
error: function(xhr, ajaxOptions, thrownError){
alert(xhr.status);
alert(ajaxOptions);
alert(thrownError);
},
beforeSend: function() {
return $('#htmlForm').validate().form();
},
success: function() {
$('#formDiv').html('<div id="message"></div>');
$('#message').html('<h2>Thank You!</h2>')
.append('<h3>Your sighting has been reported</h3>')
return false;
}
});
return false;
};
我已经惊动了jQuery的AJAX错误,我越来越:
警报(XHR); => 0
警报(thrownError)=>错误
http://jsfiddle.net/rhewitt/u3C4U/
你用萤火虫看到什么? – gdoron 2012-04-04 18:00:05
你期望什么,你的成功函数是以返回false开始的,这不是它应该做什么?如果是这样,将返回false放在成功函数的底部! – adeneo 2012-04-04 18:00:46
有没有机会得到repro @ jsfiddle ......否则就像在周围钓鱼...... – 2012-04-04 18:11:39