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我有建立用户对象的集合从所述数据库的函数：PHP函数的返回值嵌套阵列中移除
public static function GetUsersByGroup($instanceID, $groupID)
{
$col = null;
if($groupID != null)
{
$col = UserGroup::GetCollection("User" ,_DB_GET_ALL_INSTANCE_USERGROUP_MEMBERS,array ($instanceID, $groupID));
}
else
{
$col = UserGroup::GetCollection("User" ,_DB_GET_ALL_INSTANCE_NOGROUP_MEMBERS,$instanceID);
}
echo "this is the collection I am going to return: <pre>";
print_r($col);
echo "</pre>";
return $col;
}
的方法具有在底部一些调试输出，但问题是，如果我调用方法与一个空的groupid参数即它运行第二个条件，它打印出一个很好的指示我期望收到的集合，这是很好的。
但是..
这里是我的调用方法：
echo "<br> Collection passed through is: </br>";
$collection = UserGroup::GetUsersByGroup($this->GetInstance()->id,$grouplist->GetCurrentCommandParam());
print_r($collection);
$userlist->UpdateCollection($collection);
$userlist->DeSelect();
的intresting东西是输出：
this is the collection I am going to return:
Collection Object
(
[_valueType:protected] => User
[_isBasicType:protected] =>
[_validateFunc:protected] =>
[_collection:protected] => Array
(
[0] => User Object
(
[valid] =>
[validationMessage] =>
[id] => 29
[table:private] => user
[fields:private] => Array
(
[title] => mrs
[fname] => Kirsty
[lname] => Howden
[email] => [email protected]
[password] => xxxxxxxx
[lastlogin] => 2009-07-05 15:20:13
[instanceID] => 2
[deliveryAddress] =>
[invoiceAddress] =>
[tel] => 01752848484
[isAdmin] => 0
[disabled] => 0
[mustAuthorise] =>
[usergroupID] =>
)
[validationRules:private] => Array
(
)
[_profileStartTime:protected] =>
[_profileTag:protected] =>
)
[1] => User Object
(
[valid] =>
[validationMessage] =>
[id] => 31
[table:private] => user
[fields:private] => Array
(
[title] => master
[fname] => Seb
[lname] => Howden
[email] => [email protected]
[password] => xxxxxxxxx
[lastlogin] => 2009-07-09 02:02:24
[instanceID] => 2
[deliveryAddress] => saltash
[invoiceAddress] => saltash
[tel] => 8908908
[isAdmin] => 0
[disabled] => 0
[mustAuthorise] =>
[usergroupID] =>
)
[validationRules:private] => Array
(
)
[_profileStartTime:protected] =>
[_profileTag:protected] =>
)
)
)
Collection passed through is:
this is the collection I am going to return:
Collection Object
(
[_valueType:protected] => User
[_isBasicType:protected] =>
[_validateFunc:protected] =>
[_collection:protected] => Array
(
)
)
Collection Object ([_valueType:protected] => User [_isBasicType:protected] => [_validateFunc:protected] => [_collection:protected] => Array ())
返回的对象已被修改？
如果使用userGroupID调用GetUsersByGroup方法（即第一种情况），则输出全部按预期方式进行。
如果我从方法中删除条件并简单地返回$col = UserGroup::GetCollection("User" ,_DB_GET_ALL_INSTANCE_NOGROUP_MEMBERS,$instanceID);那么所有输出都如预期的那样。
似乎else条件正确执行，然后在返回时被破坏，但只有在else条件存在的情况下才会发生，删除else条件并仅在else条件中返回方法调用的结果，一切都如预期。
有什么想法吗？
感谢
添加的用户组:: GetCollection方法（这是一个深刻的兔子洞虽然可以继续）
protected static function GetCollection($class, $sqlID, $params = null)
{
$dal = DAL::GetInstance(); //not to be confused with the Instance object, this is an instance of DAL
$collection = new Collection($class);
$items = $dal->QueryForAssoc($sqlID,$params);
foreach($items as $item)
{
$itemObject = new $class();
$itemObject->LoadFromList($item);
$collection->add($itemObject);
}
return $collection;
}
为了进一步澄清follwing工作正常::
public static function GetUsersByGroup($instanceID, $groupID)
{
$col = null;
//if($groupID != null)
//{
//$col = UserGroup::GetCollection("User" ,_DB_GET_ALL_INSTANCE_USREGROUP_MEMBERS,array ($instanceID, $groupID));
//}
//else
//{
$col = UserGroup::GetCollection("User" ,_DB_GET_ALL_INSTANCE_NOGROUP_MEMBERS,$instanceID);
// }
return $col;
}
如果该行在else块中，我只会看到问题。
这真的取决于功能用户组:: GetCollection - 我们需要看到的是（甚至更多），以便能够回答这个问题！ – Mez 2009-08-07 17:07:32