我在从存储文件读取序列化对象时遇到问题。 (请参阅下面的代码)。C++:自定义对象序列化/反序列化失败
序列化过程“有效”(虽然可能写得很差),并且因为无法知道用户是否传递了std :: ios :: binary标志或者没有选择不使用格式化用whitespace
输出。 (这也节省内存为大量像素数据的潜在对我并没有失去。)
我第一次尝试看起来一样的样品,但int
小号是unsigned char
s的意图位压缩的下半部分和上半部分放入char
s中,然后重新组装它们。
目前我可以读取所有的数据到一个文件中,但是当我试图读取第一片非校验和数据,要么返回0(与char
S中的尝试的情况下)或垃圾的(在的情况下与int
S上的尝试)
连载:
std::ostream& operator<<(std::ostream& os, const Sprite& data) {
int dF = data._dimensions.first;
int dS = data._dimensions.second;
int cF = data._center.first;
int cS = data._center.second;
int fF = data._frameDimensions.first;
int fS = data._frameDimensions.second;
double sF = data._scaleDimensions.first;
double sS = data._scaleDimensions.second;
std::string name(*data._file);
name.shrink_to_fit();
os << 'S' << 'P' << 'R' << (name.length() + 1) << name.c_str() << dF << dS << cF << cS << fF << fS << sF << sS;
for(int x = 0; x < data._dimensions.first; ++x) {
for(int y = 0; y < data._dimensions.second; ++y) {
int color = getpixel(data._image, x, y);
os << static_cast<unsigned char>(getr(color)) << static_cast<unsigned char>(getg(color)) << static_cast<unsigned char>(getb(color));
}
}
int tint = data._tint;
os << static_cast<unsigned char>(getr(tint)) << static_cast<unsigned char>(getg(tint)) << static_cast<unsigned char>(getb(tint));
os << data._tintIntensity << data._alpha;
return os;
}
反序列化:
std::istream& operator>>(std::istream& is, Sprite& data) {
char checksum[3];
is >> checksum[0] >> checksum[1] >> checksum[2];
if(checksum[0] != 'S' || checksum[1] != 'P' || checksum[2] != 'R') {
is.setstate(std::ios::failbit);
return is;
}
int name_length;
is >> name_length;
std::string name(name_length, '\0');
for(int i = 0; i <= name_length; ++i) {
char current_char = '\0';
is >> current_char;
name[i] = current_char;
}
int upper = 0;
int lower = 0;
is >> upper;
is >> lower;
data._dimensions.first = (upper << 8) | lower;
upper = 0;
lower = 0;
is >> upper >> lower;
data._dimensions.second = ((upper << 8) | lower);
upper = 0;
lower = 0;
is >> upper >> lower;
data._center.first = ((upper << 8) | lower);
upper = 0;
lower = 0;
is >> upper >> lower;
data._center.second = ((upper << 8) | lower);
upper = 0;
lower = 0;
is >> upper >> lower;
data._frameDimensions.first = ((upper << 8) | lower);
upper = 0;
lower = 0;
is >> upper >> lower;
data._frameDimensions.second = ((upper << 8) | lower);
double f = 0.0;
double s = 0.0;
is >> f >> s;
data._scaleDimensions.first = f;
data._scaleDimensions.second = s;
destroy_bitmap(data._image);
data._image = NULL;
data._image = create_bitmap(data._dimensions.first, data._dimensions.second);
for(int x = 0; x < data._dimensions.first; ++x) {
for(int y = 0; y < data._dimensions.second; ++y) {
unsigned char r = 0;
unsigned char g = 0;
unsigned char b = 0;
is >> r >> g >> b;
int color = ((r << 16) | (g << 8) | b); //0xRRGGBB
putpixel(data._image, x, y, color);
}
}
unsigned char rtint = 0;
unsigned char gtint = 0;
unsigned char btint = 0;
is >> rtint >> gtint >> btint;
data._tint = ((rtint << 16) | (gtint << 8) | btint); //0xRRGGBB
is >> data._tintIntensity;
is >> data._alpha;
return is;
}
什么具有格式标志'std :: ios_base :: binary'做与不做格式化I/O?该标志只是决定如何处理行结束符:当以非二进制模式写入'\ n'时,它可能被替换(例如通过CR/LF),而在二进制模式下它不会被替换。类似地,当读取结束行序列被非二进制模式中的单个'\ n'替换或以二进制模式保持原样时。为防止用户使用或不使用此标志打开,您应该使用格式化的I/O! – 2012-01-08 23:40:01
查看代码:在不插入空格的情况下编写多个值将导致'std :: istream'读取一个较大的值而不是多个较小的值。可能这个大值会导致溢出错误,从而导致数据流进入不良状态。这就是你的问题开始的地方...... – 2012-01-08 23:42:33
@DietmarKühl:做出答案并且我会接受它。 :d – Casey 2012-01-09 03:04:02