这里的另一种方式来整齐地接近它这避免宏。
请注意在这种情况下，我将日志记录发送到标准输出，但可以很容易地进行修改。我也使用std::ostringstream来构建日志消息。它的表现并不出名，因此是定制点的理想选择。
然而，这应该让你开始，如果你喜欢的方式：
#include <iostream>
#include <sstream>
#include <tuple>
#include <utility>
// define a constant index type
template<std::size_t N> using index_c = std::integral_constant<std::size_t, N>;
// emitting an item at index 0 has no prefix
template<class T>
void emit_item(std::ostream &os, index_c<0>, T const &t)
{
os << t;
}
// emitting an item at index N (!= 0) has a comma prefix
template<std::size_t N, class T>
void emit_item(std::ostream &os, index_c<N>, T const &t)
{
os << ", " << t;
}
// emit args 0 .. N-1
template<class Tuple, std::size_t...Is>
void emit_arglist(std::ostream &sink, Tuple &&tuple, std::index_sequence<Is...>)
{
using expand = int[];
void(expand{0,
(emit_item(sink, index_c<Is>(), std::get<Is>(tuple)), 0)...
});
};
// emitting a 'more' at index 0 has a prefix
template<class T>
void emit_more(std::ostream &os, index_c<0>, T const &t)
{
os << " : " << t;
}
// emitting a 'more' at index N (!= 0) has a space prefix
template<std::size_t N, class T>
void emit_more(std::ostream &os, index_c<N>, T const &t)
{
os << " " << t;
}
template<class Tuple, std::size_t...Is>
void emit_more(std::ostream &sink, Tuple &&tuple, std::index_sequence<Is...>)
{
using expand = int[];
void(expand{0,
(emit_more(sink, index_c<Is>(), std::get<Is>(tuple)), 0)...
});
};
template<typename... Args, typename ...MoreStuff>
std::string
make_log_string(const char *object,
char const *func,
std::tuple<Args const &...> const& args,
MoreStuff&&...morestuff) noexcept
{
std::ostringstream ss;
ss << object << "::" << func << '(';
emit_arglist(ss, args, std::make_index_sequence<sizeof...(Args)>());
ss << ')';
emit_more(ss, std::tie(morestuff...), std::make_index_sequence<sizeof...(MoreStuff)>());
return ss.str();
}
// syntactic sugar for indicating arguments
template<class...Arg>
decltype(auto) args(Arg const&...args)
{
return std::tie(args...);
}
int main()
{
int a = 0, b = 1, c = 2;
std::string sa = "xxx", sb = "yyy", sc = "zzz";
const char* Class = "foo";
const char* Func = "var";
std::cout << make_log_string(Class, Func, args(a, b, c)) << std::endl;
std::cout << make_log_string(Class, Func, args(sa, b, sc)) << std::endl;
std::cout << make_log_string(Class, Func, args(sa, b, sc), "more stuff") << std::endl;
std::cout << make_log_string(Class, Func, args(), "empty", "argument", "list") << std::endl;
}
预期输出：
foo::var(0, 1, 2)
foo::var(xxx, 1, zzz)
foo::var(xxx, 1, zzz) : more stuff
foo::var() : empty argument list
并且以位更多的样板，我们可以这样写：
std::cout << make_log_string(method(Class, Func)(a, b, c)) << std::endl;
std::cout << make_log_string(method(Class, Func)(sa, b, sc)) << std::endl;
std::cout << make_log_string(method(Class, Func)(sa, b, sc), "more stuff") << std::endl;
std::cout << make_log_string(method(Class, Func)(), "empty", "argument", "list") << std::endl;
它在这里：
#include <iostream>
#include <sstream>
#include <tuple>
#include <utility>
template<std::size_t N> using index_c = std::integral_constant<std::size_t, N>;
template<class T>
void emit_item(std::ostream &os, index_c<0>, T const &t)
{
os << t;
}
template<std::size_t N, class T>
void emit_item(std::ostream &os, index_c<N>, T const &t)
{
os << ", " << t;
}
template<class Tuple, std::size_t...Is>
void emit_arglist(std::ostream &sink, Tuple &&tuple, std::index_sequence<Is...>)
{
using expand = int[];
void(expand{0,
(emit_item(sink, index_c<Is>(), std::get<Is>(tuple)), 0)...
});
};
template<class T>
void emit_more(std::ostream &os, index_c<0>, T const &t)
{
os << " : " << t;
}
template<std::size_t N, class T>
void emit_more(std::ostream &os, index_c<N>, T const &t)
{
os << " " << t;
}
template<class Tuple, std::size_t...Is>
void emit_more(std::ostream &sink, Tuple &&tuple, std::index_sequence<Is...>)
{
using expand = int[];
void(expand{0,
(emit_more(sink, index_c<Is>(), std::get<Is>(tuple)), 0)...
});
};
template<class...Args>
struct method_with_args;
struct method
{
constexpr method(const char* c, const char* f) : klass(c), func(f) {}
const char* klass;
const char* func;
template<class...Args>
auto operator()(Args const&...args) -> method_with_args<Args...>;
friend std::ostream& operator<<(std::ostream& os, const method& m)
{
return os << m.klass << "::" << m.func;
}
};
template<class...Args>
struct method_with_args
{
friend std::ostream& operator<<(std::ostream& os, method_with_args const& ma)
{
os << ma.m << '(';
emit_arglist(os, ma.args, std::make_index_sequence<sizeof...(Args)>());
return os << ')';
}
method m;
std::tuple<Args const&...> args;
};
template<class...Args>
auto method::operator()(Args const&...args) -> method_with_args<Args...>
{
return method_with_args<Args...>{*this, std::tie(args...)};
}
struct function
{
const char* name;
};
template<typename Method, typename ...MoreStuff>
std::string
make_log_string(Method m,
MoreStuff &&...morestuff) noexcept
{
std::ostringstream ss;
ss << m;
emit_more(ss, std::tie(morestuff...), std::make_index_sequence<sizeof...(MoreStuff)>());
return ss.str();
}
int main()
{
int a = 0, b = 1, c = 2;
std::string sa = "xxx", sb = "yyy", sc = "zzz";
const char *Class = "foo";
const char *Func = "var";
std::cout << make_log_string(method(Class, Func)(a, b, c)) << std::endl;
std::cout << make_log_string(method(Class, Func)(sa, b, sc)) << std::endl;
std::cout << make_log_string(method(Class, Func)(sa, b, sc), "more stuff") << std::endl;
std::cout << make_log_string(method(Class, Func)(), "empty", "argument", "list") << std::endl;
}
也许这是一个错字，但你弄乱了宏中参数的顺序。 – Holt
符号查找错误不是段错误。看起来你正试图调用一个尚未编译的'log_device_message_template'的实例。为什么实例化不存在是任何人的猜测。我们可能需要查看包装这个Python库的细节。 – cdhowie