我的情况如下,我有两个不同的平分函数,在我的代码中的某个点将被调用。基本上有些函数调用Bisection2,该函数调用传递的函数或将函数指针传递给Bisection函数。传递成员函数指针
在标头,我
std::vector<double> F();
double F1(double m1, double m2);
double F2(double m1, double m2);
typedef double (MyClass::*MyClassFn)(double,double);
double Bisection(MyClassFn fEval,double min, double max,std::vector<double> args);
bool Bisection2(MyClassFn fEval1,MyClassFn fEval2,double xmin, double xmax, double ymin, double ymax,double *ax, double *ay,std::vector<double> args);
而我的二分功能如下所示。我没有包含所有的代码,因为它没有必要。
double MyClass::F1(double m1, double m2) {
m_m1 = m1;
m_m2 = m2;
F();
return m_my;
}
double MyClass::F2(double m1, double m2) {
m_m1 = m1;
m_m2 = m2;
F();
return m_mx;
}
double MyClass::Bisection(MyClass fEval,double min, double max,std::vector<double> args)
{
// Setting a lot of stuff here, including auxiliary and leftvalue...
MyClass *pObj = new MyClass(-1);
leftvalue = pObj->*fEval(auxiliary, left);
ightvalue = pObj->*fEval(auxiliary, right);
// Comparing and setting values here etc.
}
bool MyClass::Bisection2(MyClassFn fEval1,MyClassFn fEval2,double xmin, double xmax, double ymin, double ymax,double *ax, double *ay,std::vector<double> args)
{
// Setting some values here but these have nothing to do with the problem.
double yl;
double leftvalue, rightvalue, middlevalue;
MyClass *pObj = new MyClass(-1);
// Setting some values here but these have nothing to do with the problem.
std::vector <double> arg;
// pushing some values
yl = Bisection(fEval2,ymin,ymax,arg); // Here is the first way how I need to pass fEval2 to Bisection function.
arg.clear();
if(isnan(yl))
{
return M_NAN;
}
leftvalue = pObj->fEval1(xl, yl); // And here is the second way how I need to use fEval1.
//.....
}
然后,我已经基本功能什么叫
`Bisection2(F1,F2,m_m2,0.0,0.0,m_max2,& m_mu1,& m_mu2,参数);
Bisection2(...)调用此时可能不正确,因为自上次工作以来,我已经更改了很多功能。上次我基本上直接在函数内部调用F1和F2函数指针而不是fEval,但我确信这是不正确的方式,毕竟即使它认为它似乎工作。
现在leftvalue = pObj - > * fEval(auxiliary,left);导致编译错误:
error: must use ‘.*’ or ‘->*’ to call pointer-to-member function in ‘fEval (...)’, e.g. ‘(... ->* fEval) (...)’
我想看看帮助从这里http://www.parashift.com/c++-faq-lite/pointers-to-members.html#faq-33.2 还检查了这些论坛,也许不同的解决问题,但仍然无法弄清我做错了。
谢谢。
在'Bisection'参数'的*定义* fEval'被声明为具有'MyClass'类型。这是不正确的。它应该是'MyClassFn',因为它在'Bisection'的声明中。 – AnT