将MySQL INNER JOIN的结果合并到一个PHP数组中

Question

我有两张表，我想将它们合并成一个，但不是所有字段。我使用INNER JOIN取得了一些成功，但无法获得我需要的确切结果。实质上，当使用PHP返回结果时，我希望关键是'meta_key'值。

下面是两个表我想结合：

USERS 
+--------+-----------------+------------------+----------------+ 
| ID | username  | first_name  | last_name  | 
+--------+-----------------+------------------+----------------+ 
| 2 | hthompson  | Hunter   | Thompson  | 
| 7 | coak   | Carol   | Oak   | 
| 8 | delk   | Dannie   | Elk   | 
| 9 | mride   | Mark    | Ride   | 
| 10 | kken   | Kyle    | Ken   | 
| 11 | glee   | Ginny   | Lee   | 
| 12 | nwatts   | Naomi   | Watts   | 
| 13 | jwong   | Jin    | Wong   | 
| 14 | syin   | Shen    | Yin   | 
+--------+-----------------+------------------+----------------+ 

USERS_META 
+--------+--------+-----------------+------------------+ 
| ID | UID | meta_key  | meta_value  | 
+--------+--------+-----------------+------------------+ 
| 1 | 2 | business_name | Company Inc.  | 
| 2 | 2 | city   | New York   | 
| 3 | 2 | state   | NY    | 
| 5 | 9 | city   | Boston   | 
| 6 | 9 | state   | MA    | 
| 7 | 11 | business_type | Printer   | 
| 8 | 8 | chamber_member | true    | 
| 9 | 2 | business_type | Design   | 
+--------+--------+-----------------+------------------+ 

下面是想我回一个例子：

USERS 
+--------+-----------------+------------+------------+------------------+ 
| ID | username  | city  | state  | business_name | 
+--------+-----------------+------------+------------+------------------+ 
| 2 | hthompson  | New York | NY   | Company Inc.  | 
+--------+-----------------+------------+------------+------------------+ 

OR

$user['ID'] = 2 
$user['username'] = hthompson 
$user['city'] = New York 
$user['state'] = NY 
$user['business_name'] = Company Inc. 

离我最近的com e是这样的：

$query = ("SELECT * 
FROM users 
INNER JOIN users_meta ON users.ID = users_meta.UID 
WHERE 
users_meta.meta_key = 'city' OR 
users_meta.meta_key = 'state' OR 
users_meta.meta_key = 'business_name' 
"); 

然而，做这样的回报三个结果为每一个独特的用户ID，我的目标在返回一个与指定的所有元信息。这样做的主要目的是让我能够使用一个关键字进行搜索，该关键字将应用于USERS.first_name，USERS.first_name和USERS_META.business_name列，然后在显示ID，Business Name，City的表中显示返回结果，状态，第一个&姓氏。

在此先感谢！

Answer 1

你可以试试这个：

SELECT 
    u.ID, 
    u.username, 
    m0.meta_value as city, 
    m1.meta_value as state, 
    m2.meta_value as business_name 
FROM 
    users u, 
    users_meta m0, 
    users_meta m1, 
    users_meta m2 
WHERE 
    u.ID = m0.UID 
     AND m0.meta_key = 'city' 
    AND u.ID = m1.UID 
     AND m1.meta_key = 'state' 
    AND u.ID = m2.UID 
     AND m2.meta_key = 'business' 

Answer 2

至于获取信息了，我只想建议一起加入表，并使用PHP，使阵列。类似的东西：

<?php 
//if search is blank, returns all rows 
$search = isset($_POST['search'])?mysql_real_escape_string($_POST['search']):''; 

//query for all rows with meta key/values including extra 
//rows from the join. extra rows will be taken out later. 
$result = mysql_query(
    "SELECT 
     U.ID, 
     U.USERNAME, 
     U.FIRST_NAME, 
     U.LAST_NAME, 
     UM.META_KEY, 
     UM.META_VALUE 
    FROM USERS U 
     JOIN USERS_META UM ON U.ID=UM.UID 
    WHERE 
     UM.META_KEY IN ('city', 'state', 'business_name') 
     AND U.FIRST_NAME LIKE '%{$search}%'"); 

//an empty array to put our results into 
$out = array(); 

//loop through the rows 
while($row=mysql_fetch_assoc($out)){ 
    //check if the user id has been added already 
    if(!isset($out[$row['ID']])){ 
     //if not, add it with generic information 
     $out[$row['ID']] = array(
      'ID'=>$row['ID'], 
      'USERNAME'=>$row['USERNAME'], 
      'FIRST_NAME'=>$row['FIRST_NAME'], 
      'LAST_NAME'=>$row['LAST_NAME']); 
    } 
    //add the meta key and value 
    $out[$row['ID']][$row['META_KEY']] = $row['META_VALUE']; 
} 

//display 
echo '<pre>'.print_r($out,1).'</pre>'; 
?>