1
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
setContentView(R.layout.question_layout);
show_popup();
}
private void show_popup(){
LayoutInflater lf = (LayoutInflater)getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View m_view = lf.inflate(R.layout.popup_question, null);
m_popup_window = new PopupWindow(m_view,500,150,false);
m_popup_window.showAtLocation(m_full_page, Gravity.CENTER, 0, 0);
}
当我上的任何按钮单击呼吁show_popup它做工精细,但是当我想show_popup()调用的onCreate(),它不能正常工作。我得到了这样的logcat上的错误显示无法启动创建弹出窗口时,活动刚开始
08-22 13:57:36.682: ERROR/AndroidRuntime(21860): at tesingimage.com.testingimagemain.show_pupup(testingimagemain.java:41)
08-22 13:57:36.682: ERROR/AndroidRuntime(21860): at tesingimage.com.testingimagemain.onCreate(testingimagemain.java:23)
08-22 13:57:36.682: ERROR/AndroidRuntime(21860): at android.app.Instrumentation.callActivityOnCreate(Instrumentation.java:1047)
请提前帮助我,谢谢!
和呼叫处理程序(在代码的方法的名称是show_popup(),在logcat的是show_pupup()。这是一个错误吗?请发布完整的异常logcat,而不仅仅是三条随机线 – Egor