我想根据接近传感器打开和关闭屏幕。我可以关闭屏幕。但在屏幕后面的代码不起作用。任何人都可以帮助我吗? 这是代码:`在android中以编程方式打开和关闭屏幕
public void onSensorChanged(SensorEvent event) {
if (event.values[0] == 0) {
Toast.makeText(getApplicationContext(), "sensor in 0",Toast.LENGTH_LONG).show();
WindowManager.LayoutParams params = getWindow().getAttributes();
params.flags |= LayoutParams.FLAG_KEEP_SCREEN_ON;
params.screenBrightness = 0;
getWindow().setAttributes(params);
} else {
Toast.makeText(getApplicationContext(), "sensor in 1",Toast.LENGTH_LONG).show();
WindowManager.LayoutParams params = getWindow().getAttributes();
params.screenBrightness = -1;
getWindow().setAttributes(params);
}
}`
[Android:如何以编程方式打开和关闭屏幕?](http://stackoverflow.com/questions/9561320/android-how-to-turn-screen-on-and-off-programmatically) –
检查此问题http://stackoverflow.com/questions/9561320/android-how-to-turn-screen-on-and-off-programmatically –
也检查此http://android.okhelp.cz/turn-screen- on-off-android-sample-code/ –