亲子关系 - SQL查询

我的来源是如下亲子关系 - SQL查询

OSPID  OSPNAME RELATEDOSPID 
100004 LEVEL4 100003 
100003 LEVEL3 100002 
100002 LEVEL2 100001 
100001 LEVEL1 0 
100009 LEVEL4 100008 
100008 LEVEL2 100007

我需要的结果作为

L4OSPID L4OSPNAME L3RELATEDID L3OSPNAME L2RELATEDID L2OSPNAME L1RELATEDID L2OSPNAME ROOTNODE 
100004 LEVEL4  100003  LEVEL3  100002  LEVEL2  100001  LEVEL1  0 
100009 LEVEL4  100008  NULL  NULL  LEVEL2  100007  NULL   NULL

如果缺少之间的任何级别应该把NULL

感谢

来源

2010-10-19 Sreedhar

是否有总是那些4级（除了丢失的记录）？ – 2010-10-19 12:28:53

Peter：是的，可能有所有4个级别的记录相关联，并且也会记录缺失的链接。 – Sreedhar 2010-10-19 12:37:55

您的最后一行指向不存在的'100007'。这是你的样品错误吗？ – 2010-10-19 12:49:08

假设只有4个LEVEL，并且您始终想从LEVEL4开始，请查询

select L4.OSPID as L4OSPID, L4.OSPNAME as L4OPSNAME, 
L4.RELATEDOSPID 
as L3RELATEDID, 

case 
    WHEN L3.OSPNAME = 'LEVEL3' THEN L3.OSPNAME 
    ELSE NULL 
end as L3OSPNAME, 

case 
    WHEN L3.OSPNAME = 'LEVEL3' THEN L3.RELATEDOSPID 
    ELSE NULL 
end as L2RELATEDID, 

case 
    WHEN L3.OSPNAME = 'LEVEL2' THEN L3.OSPNAME 
    WHEN L2.OSPNAME = 'LEVEL2' THEN L2.OSPNAME 
    ELSE NULL 
end as L2OSPNAME, 

case WHEN L3.OSPNAME = 'LEVEL2' THEN L3.RELATEDOSPID 
    WHEN L2.OSPNAME = 'LEVEL2' THEN L2.RELATEDOSPID 
    ELSE NULL 
end 
as L1RELATEDID, 

case 
    WHEN L3.OSPNAME = 'LEVEL1' THEN L3.OSPNAME 
    WHEN L2.OSPNAME = 'LEVEL1' THEN L2.OSPNAME 
    WHEN L1.OSPNAME = 'LEVEL1' THEN L1.OSPNAME 
    ELSE NULL 
end as L1OSPNAME, 

case 
    WHEN L3.OSPNAME = 'LEVEL1' THEN L3.RELATEDOSPID 
    WHEN L2.OSPNAME = 'LEVEL1' THEN L2.RELATEDOSPID 
    WHEN L1.OSPNAME = 'LEVEL1' THEN L1.RELATEDOSPID 
    ELSE NULL 
end as ROOTNODE 


from osptable as L4 

left outer join osptable as L3 
on L4.RELATEDOSPID = L3.OSPID 
left outer join osptable as L2 
on L3.RELATEDOSPID = L2.OSPID 
left outer join osptable as L1 
on L2.RELATEDOSPID = L1.OSPID 
where L4.OSPNAME = 'LEVEL4'

这给了我这样的结果，我认为这是一个希望的

100004 LEVEL4 100003 LEVEL3 100002 LEVEL2 100001 LEVEL1 0 
100009 LEVEL4 100008 NULL NULL LEVEL2 100007 NULL NULL

来源

2010-10-19 13:31:02

亲子关系 - SQL查询

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