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如何消除重复项? 它必须是10行,显示每个学生ID(1x)。 我试过这2种不同的方式。 (见下文) (共同项目是类标识码)消除重复的SQL?
SQL> select distinct(student_id),event.class_id, event.event_id, event.event_name
2 from student_class
3 inner join event on event.class_id = student_class.class_id
4 where student_class.class_id = '10'
5 order by student_id desc;
STUDENT_ID CLASS_ID EVENT_ID EVENT_NAME
---------- ---------- ---------- --------------------------------------------------
20 10 5 PICKUP SOCCER GAME
20 10 2 Flag FOOtball Game
18 10 2 Flag FOOtball Game
18 10 5 PICKUP SOCCER GAME
16 10 2 Flag FOOtball Game
16 10 5 PICKUP SOCCER GAME
12 10 5 PICKUP SOCCER GAME
12 10 2 Flag FOOtball Game
9 10 5 PICKUP SOCCER GAME
9 10 2 Flag FOOtball Game
8 10 2 Flag FOOtball Game
8 10 5 PICKUP SOCCER GAME
6 10 2 Flag FOOtball Game
6 10 5 PICKUP SOCCER GAME
4 10 5 PICKUP SOCCER GAME
4 10 2 Flag FOOtball Game
3 10 2 Flag FOOtball Game
3 10 5 PICKUP SOCCER GAME
2 10 5 PICKUP SOCCER GAME
2 10 2 Flag FOOtball Game
SQL> select distinct(student_id), student_class.class_id,
event.event_id, event.event_date_time
from student_class
inner join event on event.class_id = student_class.class_id
order by student_id desc;
STUDENT_ID CLASS_ID EVENT_ID EVENT_DAT
---------- ---------- ---------- ---------
22 9 1 09-NOV-99
21 2 6 20-NOV-99
21 9 1 09-NOV-99
20 9 1 09-NOV-99
20 10 2 19-JAN-99
20 10 5 09-JUL-99
18 9 1 09-NOV-99
18 10 2 19-JAN-99
18 10 5 09-JUL-99
17 9 1 09-NOV-99
16 2 6 20-NOV-99
16 9 1 09-NOV-99
16 10 2 19-JAN-99
16 10 5 09-JUL-99
15 9 1 09-NOV-99
14 9 1 09-NOV-99
13 9 1 09-NOV-99
12 2 6 20-NOV-99
12 9 1 09-NOV-99
12 10 2 19-JAN-99
12 10 5 09-JUL-99
11 2 6 20-NOV-99
11 9 1 09-NOV-99
9 10 2 19-JAN-99
9 10 5 09-JUL-99
8 2 6 20-NOV-99
8 10 2 19-JAN-99
8 10 5 09-JUL-99
7 2 6 20-NOV-99
6 10 2 19-JAN-99
6 10 5 09-JUL-99
4 10 2 19-JAN-99
4 10 5 09-JUL-99
3 10 2 19-JAN-99
3 10 5 09-JUL-99
2 2 6 20-NOV-99
2 9 1 09-NOV-99
2 10 2 19-JAN-99
2 10 5 09-JUL-99
喜花花公子做到这一点,不明白你的问题,你能举一些样品吗? –
在我看来,'EVENTS'表有两个class_id = 10的event_id,这就是你在输出中为每个student_id获取两行的方式 – Incognito