SQL连接多个

Question

我要合并这两个查询：

查询1 - 一个简单的内部联接，其中查询：

Select t1.c1, t1.c2, t1.c3, t2.c1 

from s1.t2 t2 
inner join s1.t1 t1 on t2.c6 = t1.c6 

where t2.c5 >= '2014-01-01' 
and t2.c5 >= '2014-01-01' 
and t1.c4 = 'P' 

这返回一个表，当然，4列。让我画出来的位置：

+----+----+----+-------+ 
| C1 | C2 | C3 | T2.C1 | 
+----+----+----+-------+ 
| | | |  | 

查询2 - 有了，那么“由分区”语句删除与复制：

WITH all_col1 (ONE, TWO) AS 
(
    SELECT col1, col2 
    FROM Schema1.Table1 
    UNION 
    SELECT col1, col2 
    FROM Schema2.Table2 
    UNION 
    SELECT col1, col2 
    FROM Schema2.Table3 
) 
SELECT * 
FROM (
    SELECT ONE, TWO, 
    ROW_NUMBER() OVER(PARTITION BY ONE ORDER BY ONE) duplicate_count 
    FROM all_col1 
) all_col1_w_duplicat_count 
WHERE duplicate_count = 1 

这将返回两列，以去掉，（这意味着所有重复如果第1列有重复多余的行被显式删除）：

+-----+-----+ 
| ONE | TWO | 
+-----+-----+ 
|  |  | 

所以我想看到的是第一个查询和第二查询合并这样的，其中两个被添加到表，其中ONE matches C1：

+------+----+----+-------+-----+ 
| C1 | C2 | C3 | T2.C1 | TWO | 
|(ONE) | | |  |  | 
+------+----+----+-------+-----+ 
|  | | |  |  | 

所以，我试过了INTERSECT，添加了占位符行。返回空。

我试图让查询1 CTE，然后加入两个 - 得到了无数的错误尝试。

这里是我已经能够拿出这么迄今为止最好的 - 在查询2中的SELECT语句中加入查询1：

--ALL COL1 WITH beginning 

WITH all_col1 (ONE, TWO) AS 
(
    SELECT col1, col2 
    FROM Schema1.Table1 
    UNION 
    SELECT col1, col2 
    FROM Schema2.Table2 
    UNION 
    SELECT col1, col2 
    FROM Schema2.Table3 
) 


--ALL COL1 SELECT duplicate_count 

SELECT * 
FROM (
    SELECT ONE, TWO, 
    ROW_NUMBER() OVER(PARTITION BY ONE ORDER BY ONE) duplicate_count 
    FROM all_col1 


    -- added join opperation 

    join (


     --SELECT from query 1 

     Select t1.c1, t1.c2, t1.c3, t2.c1 

     from s1.t2 t2 
     inner join s1.t1 t1 on t2.c6 = t5.c6 

     where t2.c5 >= '2014-01-01' 
     and t2.c5 >= '2014-01-01' 
     and t1.c4 = 'P' 


    -- finish join opperation 

    ) as query1 
    on all_col1.ONE = query1.c1 -- <----MOST IMPORTANT PART 


-- finsih ALL COL1 

) all_col1_w_duplicat_count 
WHERE duplicate_count = 1 

此，不幸的是，不给我，结果加入了每个查询的第一列正在试图询问on all_col1.ONE = t1.c1

相反，它似乎只是给了我WITH ALL_col1。

我对sql几乎一无所知，为了正确地将这两个查询连接在一起，我需要学习什么？

Answer 1

考虑由两个派生表（子查询FROM和JOIN条款）为您的副本计数加盟包括两个表，而不是只有一个：

... 
SELECT q.c1, q.c2, q.c3, q.t2_c1, a.[TWO] 
FROM 
    (
    SELECT * 
    FROM (
      SELECT ONE, TWO, 
      ROW_NUMBER() OVER(PARTITION BY ONE ORDER BY ONE) duplicate_count 
      FROM all_col1 
     ) sub 
    WHERE sub.duplicate_count = 1 
) a 

INNER JOIN 
    (
    SELECT t1.c1, t1.c2, t1.c3, t2.c1 as t2_c1 
    FROM s1.t2 t2 
    INNER JOIN s1.t1 t1 on t2.c6 = t5.c6 
    WHERE t2.c5 >= '2014-01-01' 
    AND t2.c5 >= '2014-01-01' 
    AND t1.c4 = 'P' 
) q 

ON a.ONE = q.c1