6
我如何把这个左连接查询:Zend公司如何创建一个LEFT JOIN
select advertisercontest.*, advertiseraccount.advertiserid, advertiseraccount.companyname
from advertisercontest
left join advertiseraccount on advertiseraccount.loginid = advertisercontest.loginid
where advertisercontest.golive is not NULL;
到左加入Zend的?
太棒了!谢谢!我有个问题。我扩展了Zend_Db_Table_Abstract,并且我有这个: $ rows = $ this-> select() - > from('advertisercontest','*') - > joinLeft('advertiseraccount','advertiseraccount.loginid = advertisercontest。 ('advertisercontest.golive is not NULL') - > order('advertisercontestid DESC'); - > order('advertisercontestid DESC'); - > order('advertisercontestid DESC'); 但它没有工作?但你的例子..我在我的applications.ini resources.db.isDefaultTableAdapter = true – coder3 2011-02-10 22:03:56