标题可能不是很描述导航,但我想不出一个更好的。如何在一个圆圈
的问题是如下: 我有一个屏幕(ScreenOne)以链接到另一屏幕(ScreenTwo)。 ScreenTwo是一个返回到ScreenOne的链接。
我通过自定义RichTextFields和自定义ChangeListener实现这一点。
现在的问题是,我总是收到的StackOverflowError! 有什么方法来回导航吗?
问候亚光
public class MyApp extends UiApplication
{
public static void main(String[] args)
{
MyApp theApp = new MyApp();
theApp.enterEventDispatcher();
}
public MyApp()
{
ScreenOne so = ScreenProvider.getInstance().getScreenOne();
so.initialize();
ScreenProvider.getInstance().getScreenTwo().initialize();
pushScreen(so);
}
}
public class ScreenOne extends MainScreen {
MyTextField link;
public ScreenOne() {
link = new MyTextField("FirstScreen");
add(link);
}
public void initialize(){
link.setChangeListener((FieldChangeListener) new MyFieldChangeListener(ScreenProvider.getInstance().getScreenTwo()));
}
}
public class ScreenTwo extends MainScreen {
MyTextField link;
public ScreenTwo() {
link = new MyTextField("SecondScreen");
add(link);
}
public void initialize(){
link.setChangeListener((FieldChangeListener) new MyFieldChangeListener(ScreenProvider.getInstance().getScreenOne()));
}
}
public class MyFieldChangeListener implements FieldChangeListener {
private Screen nextScreen;
public MyFieldChangeListener(Screen nextScreen) {
this.nextScreen = nextScreen;
}
public void fieldChanged(Field field, int context) {
UiApplication.getUiApplication().pushScreen(nextScreen);
}
}
public class MyTextField extends RichTextField {
public MyTextField() {
super();
}
public MyTextField(String text) {
super(text);
}
protected boolean touchEvent(TouchEvent message) {
if (TouchEvent.CLICK == message.getEvent()) {
FieldChangeListener listener = getChangeListener();
if (null != listener)
listener.fieldChanged(this, 1);
}
return super.touchEvent(message);
}
}
public class ScreenProvider {
private static ScreenProvider instance = null;
private ScreenProvider(){}
public static ScreenProvider getInstance() {
if (instance == null) {
instance = new ScreenProvider();
}
return instance;
}
private ScreenOne screenOne = new ScreenOne();
private ScreenTwo screenTwo = new ScreenTwo();
public ScreenOne getScreenOne() {
return screenOne;
}
public ScreenTwo getScreenTwo() {
return screenTwo;
}
}
你能张贴代码吗? – mellamokb 2011-02-25 16:24:04