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我有一个触发器，我想从存储过程中将其启动。我使用MS访问，当我从MS访问运行触发它给我一个错误消息（ODBC）。我想我不能使用ms访问创建触发器。这是我的触发器：使用存储过程创建触发器
IF EXISTS
(SELECT name
FROM sys.objects
WHERE name = 'UpdateComments' AND type = 'TR')
DROP TRIGGER tblEmailHdr_abenit01.UpdateComments;
GO
CREATE TRIGGER UpdateComments
ON tblEmailHdr_abenit01
AFTER Update
AS
IF (UPDATE (Comments)) BEGIN Update ttblEmailHdr_abenit01
Set UpdateComm = GetDate()
END;
GO
这是我怎么一直在试图创建存储过程的触发器，但我得到以下错误味精的，当我尝试创建存储过程：
存储过程：
CREATE PROCEDURE dbo.SP_AS_tblEmailHdr_Trig (@UserID as varchar(10))
AS
BEGIN
-- SET NOCOUNT ON added to prevent extra result sets from
-- interfering with SELECT statements.
--SET NOCOUNT ON;
-- Insert statements for procedure here
Declare @UserTable Varchar(50)
Declare @UserTable2 Varchar(50)
Set @UserTable = 'tblEmailHdr_' + @UserID ;
Set @UserTable2 = 'tblEmailHdr_' + @UserID + '.UpdateComments' ;
IF EXISTS
(SELECT name
FROM sys.objects
WHERE name = 'UpdateComments' AND type = 'TR') DROP TRIGGER @UserTable2
GO
CREATE TRIGGER UpdateComments
ON @UserTable
AFTER UPDATE
AS
IF (UPDATE (Comments))
BEGIN
--RAISERROR (50009, 16, 10)
Update @UserTable
Set UpdatedComm = GetDate()
END
GO
END
GO
错误味精，我得到：
Msg 102, Level 15, State 1, Procedure SP_AS_tblEmailHdr_Trig, Line 23
Incorrect syntax near '@UserTable2'.
Msg 102, Level 15, State 1, Procedure UpdateComments, Line 2
Incorrect syntax near '@UserTable'.
Msg 1087, Level 15, State 2, Procedure UpdateComments, Line 8
Must declare the table variable "@UserTable".
Msg 102, Level 15, State 1, Line 2
Incorrect syntax near 'END'.
从SP – Vikram 2012-02-21 01:34:21
@Vikram内取出GO' GO'可能会阻止程序被创建，但它仍然不会导致触发器被执行，因为OP似乎需要。 – Yuck 2012-02-21 01:35:28
@Yuck：你说得对。触发器会自动执行..但我认为他正在尝试创建一个。 – Vikram 2012-02-21 01:39:29