颜色matplotlib强度方面

Question

我想知道如何绘制颜色的强度方面使用python。 例如，我有一个列表[0.1,0.5,1.0]，我想用1.0圈最暗圆圈，第二个最黑圈圈圈为0.5，第三个最黑圈圈圈圈为0.1。

非常感谢您的帮助。

Answer 1

使用matplotlib，你可以做这样的事情：

from __future__ import division 
from matplotlib import pyplot as plt 
import numpy as np 

plt.ion() 

centers = [0.1, 0.5, 1.0] 
radii = [0.1, 0.2, 0.3] 
num_circs = len(centers) 

# make plot 
fig, ax = plt.subplots(figsize=(6, 6)) 
red = np.linspace(0, 1, num_circs) 
green = 0. * red 
blue = 1. - red 
colors = np.array([red, green, blue]).T 
power = 1.5 # adjust this upward to make brightness fall off faster 
for ii, (center_x, radius) in enumerate(zip(centers, radii)): 
    color = colors[ii] 
    brightness = ((num_circs-ii)/num_circs)**power # low ii is brighter 
    color = color * brightness 
    circle = plt.Circle((center_x, 0.), radius, color=color) 
    ax.add_artist(circle) 
_ = plt.axis([-0.3, 1.5, -0.9, 0.9], 'equal') 
plt.savefig('circles.png') 

产生这样的：