-2
让我把场景： 如果“学生”节点具有相同的子元素，然后合并“学生”节点。在这种情况下，如果在具有相同值的其他'学生'节点中找到'名称'节点，则需要将这2个'学生'节点与独特元素合并。在这种情况下，'名称'节点相同来了1次，'地址'节点来了2次。 同样输入XML可以有不同的子节点集合，每次可以有不同的名称。 下面是输入XML合并父节点，如果子节点相同的XML
<Root>
<Student>
<Name>Tim</Name>
<Address>
<City>
<Location1>MEL</Location1>
</City>
</Address>
</Student>
<Student>
<Name>Tim</Name>
<Address>
<City>
<Location1>DEL</Location1>
</City>
</Address>
</Student>
<Student>
<Name>1</Name>
<FatherName>Papa</FatherName>
<Address>
<Suburb>1</Suburb>
<City>
<Location1>HNL</Location1>
</City>
</Address>
</Student>
<Student>
<Name>1</Name>
<MotherName>Mom</MotherName>
<Address>
<City>
<Location1>HNL</Location1>
</City>
</Address>
</Student>
</Root>
预期的XML：
<Root>
<Student>
<Name>Tim</Name>
<Address>
<City>
<Location1>MEL</Location1>
</City>
</Address>
<Address>
<City>
<Location1>DEL</Location1>
</City>
</Address>
</Student>
<Student>
<Name>1</Name>
<FatherName>Papa</FatherName>
<Address>
<Suburb>1</Suburb>
<City>
<Location1>HNL</Location1>
</City>
</Address>
</Student>
<Student>
<Name>1</Name>
<MotherName>Mom</MotherName>
<Address>
<City>
<Location1>HNL</Location1>
</City>
</Address>
</Student>
</Root>
我试着用下面的代码来实现。我知道它效率不高。
var newdoc = XDocument.Parse(input);
// 'restriction' is the concerned node
foreach (var element in newdoc.Descendants("restriction"))
{
if (skiptimes > 0)
{
skiptimes--;
continue;
}
//Get distinct node names for 'element'
var distinctNodeName = element.Elements().Select(cc => cc.Name).Distinct();
//delete if found 'freetext' node as the this do not need to be comapared
distinctNodeName = distinctNodeName.Where(n => n.LocalName.ToString() != "FreeText");
//Get distinct elements
var distinctElementName = element.Elements().Select(xx => xx).Distinct();
foreach (var nextelement in element.ElementsAfterSelf())
{
if (!nextelement.IsEmpty)
{
//Get distinct node names for 'nextelement'
var distinctNodeName2 = nextelement.Elements().Select(xx => xx.Name).Distinct();
//delete if found 'freetext' node as the this do not need to be comapared
distinctNodeName2 = distinctNodeName2.Where(n => n.LocalName.ToString() != "FreeText");
//Get distinct elements
var distinctElements2 = nextelement.Elements().Select(xx => xx).Distinct();
//From 'element' excluding the 'StopoverSegs' node which by default always come as last node
var subelements = element.Elements().Take(distinctNodeName.Count() - 1);
//From 'nextelement' excluding the 'StopoverSegs' node which by default always come as last node
var sub2 = nextelement.Elements().Take(distinctNodeName2.Count() - 1);
// Compare node name counts which are selected as distinct
if (distinctNodeName.Count() == distinctNodeName2.Count())
{
ArrayList fir = new ArrayList();
int arrcount = 0; ArrayList sec = new ArrayList();
//Add 'element' to array list for comparison
foreach (var firstSet in subelements)
{
fir.Add(firstSet.ToString()); arrcount++;
}
//Add 'nextelement' to array list for comparison
foreach (var secondSet in sub2)
{
sec.Add(secondSet.ToString());
}
//comparison . I could not get through to compare via SequenceEqual or other custom
//extension
for (int i = 0; i < arrcount; i++)
{
if (fir[i].ToString().Trim() != sec[i].ToString().Trim())
{
GotEqual = false;
break;
}
else
{
GotEqual = true;
}
}
if (GotEqual)
{
element.Add(nextelement.Elements().Except(element.Elements(), new ElementComparer()));
skiptimes++;
}
else
{
break;
}
}
}
}
finalXML.Add(element);
}
如果您格式化xml，发布期望的xml，您尝试过的代码并询问您的具体问题，您可能会得到答案。 – 2014-09-25 16:51:50