IndexError：列表索引超出范围

-5

我可以得到任何帮助，找出代码有什么问题吗？它给了我这个错误，当我运行它：IndexError：列表索引超出范围

Traceback (most recent call last): 
    File "ap_settings.py", line 19, in <module> 
    AP_NUMBER = SETTINGS[TEST_SETTINGS_INDEX][0] 
IndexError: list index out of range

这是文件ap_settings.py：

# Define variables 
# SETTINGS is [ (AP_NUMBER, SAVE_RESULTS, SKIP) ] 

TEST_SETTINGS_INDEX = 3 

SETTINGS = [ 
      (0, 0, 0), 
      ] 

# Defining the fuzzing MAC address device 
STA_MAC = "00:20:A6:61:2D:09" 

# Defining the injection interface 
IFACE = "ath0" 

##### BELOW VARIABLES SHOULD NOT BE TWEAKED BY THE USER 

AP_NUMBER = SETTINGS[TEST_SETTINGS_INDEX][0] 
SAVE_RESULTS = SETTINGS[TEST_SETTINGS_INDEX][1] 
SKIP = SETTINGS[TEST_SETTINGS_INDEX][2] 

# Defining fuzzing specific variables 
AP = [ 
     ('kikoo', '00:11:22:33:44:55', 11, 'WPA-PSK'), 
     ][AP_NUMBER] 

SSID = AP[0] 
AP_MAC = AP[1] 
CHANNEL = chr(AP[2]) 
AP_CONFIG = AP[3] 

# Defining the number of retries when authenticating/associating to the AP 
CRASH_RETRIES = 10 
DELAY = 1 
STATE_WAIT_TIME = 2 
DELAY_REBOOT = 10 
LOG_LEVEL = 3 
CRASH_THRESHOLD = 3 
TRUNCATE = True 

# Defining the log file 
FNAME = [None, 'audits/ap-%s-%s.session' % (AP_MAC, AP_CONFIG)][SAVE_RESULTS]

来源

2016-03-17 Raveena

你有没有听说过PEP8风格约定蟒蛇？对于命名变量，所有上限都不是合适的python样式。它的工作原理是 – MarkyPython

在你的文件的顶部，你有这样的：

TEST_SETTINGS_INDEX = 3 
SETTINGS = [ 
      (0, 0, 0), 
      ]

然后再往下看，你有这个：

AP_NUMBER = SETTINGS[TEST_SETTINGS_INDEX][0] 
SAVE_RESULTS = SETTINGS[TEST_SETTINGS_INDEX][1] 
SKIP = SETTINGS[TEST_SETTINGS_INDEX][2]

您尝试访问索引位置的SETTINGS3因为这是TEST_SETTINGS_INDEX设置为，但SETTINGS只中有一个项目，所以你应该在指数0寻找：

AP_NUMBER = SETTINGS[0][0] 
SAVE_RESULTS = SETTINGS[0][1] 
SKIP = SETTINGS[0][2]

来源

2016-03-17 09:58:30

。非常感谢。 – Raveena

设置列表中包含了（0,0,0）的元组，所以基本上你的列表只包含一个元素。即len(SETTINGS)=1

因此您的代码表示

AP_NUMBER=SETTINGS[TEST_SETTINGS_INDEX][0]

其中TEST_SETTINGS_INDEX = 3，I：E

AP_NUMBER=SETTINGS[3][0]

，这意味着你正在访问不存在该列表的第三个元素，这是为什么你会得到错误'索引超出范围'。

另外列表包含n个元素，然后访问第n个元素，你需要使用n-1。例如

x = [1,2,3,4] then x[0]=1, x[1]=2, x[2]=3, x[3]=4

你的情况的代码

所以应该是

AP_NUMBER = SETTINGS[0][TEST_SETTINGS_INDEX]

此外，由于在设置列表元组的len为3 I：E

len((0,0,0)) = 3

因此您TEST_SETTINGS_INDEX的价值应范围从0到2

AP_NUMBER = SETTINGS[0][0] 
AP_NUMBER = SETTINGS[0][1] 
AP_NUMBER = SETTINGS[0][2]

欲了解更多信息请参阅list and tuples

来源

2016-03-17 10:52:26

IndexError：列表索引超出范围

回答

相关问题