如何用匹配的转换替换重新匹配？

Question

例如，我有一个字符串：

The struct-of-application and struct-of-world 

随着re.sub，它将替换预定义的字符串匹配。如何将匹配替换为匹配内容的转换？为了获得，例如：

The [application_of_struct](http://application_of_struct) and [world-of-struct](http://world-of-struct) 

如果我写了一个简单的正则表达式((\w+-)+\w+)，并尝试使用re.sub，看来我不能用我作为替代的一部分匹配，更不用说编辑匹配的内容：

In [10]: p.sub('struct','The struct-of-application and struct-of-world') 
Out[10]: 'The struct and struct' 

Answer 1

使用function for the replacement

s = 'The struct-of-application and struct-of-world' 
p = re.compile('((\w+-)+\w+)') 
def replace(match): 
    return 'http://{}'.format(match.group()) 

>>> p.sub(replace, s) 

'The http://struct-of-application and http://struct-of-world' 
>>> 

Answer 2

试试这个：

>>> p = re.compile(r"((\w+-)+\w+)") 
>>> p.sub('[\\1](http://\\1)','The struct-of-application and struct-of-world') 
'The [struct-of-application](http://struct-of-application) and [struct-of-world](http://struct-of-world)'