在矩形内部生成随机点,很简单。你只需要生成一个随机的x坐标,范围从原点位置(在你的情况下为-75),直到它的结尾,这将是原点+宽度(-75 + 100)。 然后,你会为y坐标做同样的事情。之后,你移动到生成的位置并绘制一个点。
我的代码:
# draw random dots inside of rectangle
# @param origin: is a touple, containing `x` and `y` coordinates
# @param number_of_dots: int, number of dots
# @param size: is a touple, containing `width` and `height` of rectangle
def draw_random_dots_in_rectangle(origin, number_of_dots, size=RECTANGLE_SIZE):
# loops number_of_dots times
for _ in range(number_of_dots):
# generate a random position inside of given rectangle
# using min/max, because of possible negative coordinates
# weakness - does also place dots on the edges of the rectangle
rand_x = randint(min(origin[0], origin[0] + size[0]), max(origin[0], origin[0] + size[0]))
rand_y = randint(min(origin[1], origin[1] + size[1]), max(origin[1], origin[1] + size[1]))
# moves to the random position
move_turtle_to((rand_x, rand_y))
# creates a dot
t.dot(DOT_DIAMETER)
然而,做同样的用圆圈是不可能的。它要复杂得多,需要知识analytic geometry。在你的情况下,你需要equation of circles。有了这个,你可以计算,如果生成的位置是或不在给定的圆内。
我的代码:
# draw random dot inside of circle
# @param origin: is a touple, containing `x` and `y` coordinates
# @param number_of_dots: int, number of dots
# @param radious: int, radious of circle
def draw_random_dots_in_circle(origin, number_of_dots, radius=CIRCLE_RADIOUS):
# loops number_of_dots times
for _ in range(number_of_dots):
# loops until finds position inside of the circle
while True:
# generates random x position
# subtracting radious and adding double of radious to simulate bounds of square
# which would be large enought to fit the circle
rand_x = randint(min(origin[0] - radius, origin[0] + radius * 2),
max(origin[0] - radius, origin[0] + radius * 2))
# generated random y position
# adding double of radious to sumulate bounds of square
# which would be large enought to fit the circle
rand_y = randint(min(origin[1], origin[1] + radius * 2),
max(origin[1], origin[1] + radius * 2))
# test if the generated position is in the radious
if (origin[0] - rand_x) ** 2 + (origin[1] + radius - rand_y) ** 2 < radius ** 2:
# if it is, move to the position
move_turtle_to((rand_x, rand_y))
# draw dot
t.dot(DOT_DIAMETER)
# break out from the infinite loops
break
本质上是相同的过程和以前一样,但与方程式检查。
我希望这至少有一点帮助。我自己曾经多次努力研究如何在计算机科学领域做某些事情,很多时候我发现,解析几何就是答案。所以我强烈建议至少检查一下。
我孔代码:
#!/usr/bin/env python3
import turtle
from random import randint
RECTANGLE_SIZE = 60, 80
CIRCLE_RADIOUS = 10
DOT_DIAMETER = 3
t = turtle.Turtle() # turtle object
t.speed(0) # set the fastest drawing speed
# move turtle to position without drawing
# @param: position is a touple containing `x` and `y` coordinates
def move_turtle_to(position):
t.up() # equivalent to .penuo()
t.goto(position[0], position[1])
t.down() # equivalent to .pendown()
# draws a rectangle from given origin with given size
# @param origin: is a touple, containing `x` and `y` coordinates
# @param size: is a touple, containing `width` and `height` of rectangle
def draw_rectangle(origin, size=RECTANGLE_SIZE):
# movese to the origin
move_turtle_to(origin)
# simple way of drawing a rectangle
for i in range(4):
t.fd(size[i % 2])
t.left(90)
# draws a circle from given origin with given radious
# @param origin: is a touple, containing `x` and `y` coordinates
# @param radious: int, radious of circle
def draw_circle(origin, radius=CIRCLE_RADIOUS):
# moves to the origin
move_turtle_to(origin)
# draws the circle
t.circle(radius)
# Now to what you asked
# draw random dots inside of rectangle
# @param origin: is a touple, containing `x` and `y` coordinates
# @param number_of_dots: int, number of dots
# @param size: is a touple, containing `width` and `height` of rectangle
def draw_random_dots_in_rectangle(origin, number_of_dots, size=RECTANGLE_SIZE):
# loops number_of_dots times
for _ in range(number_of_dots):
# generate a random position inside of given rectangle
# using min/max, because of possible negative coordinates
# weakness - does also place dots on the edges of the rectangle
rand_x = randint(min(origin[0], origin[0] + size[0]), max(origin[0], origin[0] + size[0]))
rand_y = randint(min(origin[1], origin[1] + size[1]), max(origin[1], origin[1] + size[1]))
# moves to the random position
move_turtle_to((rand_x, rand_y))
# creates a dot
t.dot(DOT_DIAMETER)
# draw random dot inside of circle
# @param origin: is a touple, containing `x` and `y` coordinates
# @param number_of_dots: int, number of dots
# @param radious: int, radious of circle
def draw_random_dots_in_circle(origin, number_of_dots, radius=CIRCLE_RADIOUS):
# loops number_of_dots times
for _ in range(number_of_dots):
# loops until finds position inside of the circle
while True:
# generates random x position
# subtracting radious and adding double of radious to simulate bounds of square
# which would be large enought to fit the circle
rand_x = randint(min(origin[0] - radius, origin[0] + radius * 2),
max(origin[0] - radius, origin[0] + radius * 2))
# generated random y position
# adding double of radious to sumulate bounds of square
# which would be large enought to fit the circle
rand_y = randint(min(origin[1], origin[1] + radius * 2),
max(origin[1], origin[1] + radius * 2))
# test if the generated position is in the radious
if (origin[0] - rand_x) ** 2 + (origin[1] + radius - rand_y) ** 2 < radius ** 2:
# if it is, move to the position
move_turtle_to((rand_x, rand_y))
# draw dot
t.dot(DOT_DIAMETER)
# break out from the infinite loops
break
# example code
draw_rectangle((0, 0))
draw_random_dots_in_rectangle((0, 0), 50)
draw_circle((-20, -20))
draw_random_dots_in_circle((-20, -20), 20)
input()
相关:[生成的圆内的随机点(均匀地)](http://stackoverflow.com/q/5837572/953482)。 – Kevin