这是一个后续问题是: pandas replace only part of a column大熊猫与日期时间指数仅更换一列的一部分
这里是我的电流输入:
import pandas as pd
from pandas_datareader import data, wb
import numpy as np
from datetime import date
pd.set_option('expand_frame_repr', False)
df = data.DataReader('GE', 'yahoo', date (2000, 1, 1), date (2000, 2, 1))
df['x'] = np.where (df['Open'] > df['High'].shift(-2), 1, np.nan)
print (df.round(2))
# this section of code works perfectly for an integer based index.......
ii = df[pd.notnull(df['x'])].index
dd = np.diff(ii)
jj = [ii[i] for i in range(1,len(ii)) if dd[i-1] > 2]
jj = [ii[0]] + jj
for ci in jj:
df.loc[ci:ci+2,'x'] = 1.0
# end of section that works perfectly for an integer based index......
print (df.round(2))
这里是我的电流输出:
Open High Low Close Volume Adj Close x
Date
2000-01-03 153.00 153.69 149.19 150.00 22069800 29.68 1.0
2000-01-04 147.25 148.00 144.00 144.00 22121400 28.49 1.0
2000-01-05 143.75 147.00 142.56 143.75 27292800 28.44 NaN
2000-01-06 143.12 146.94 142.63 145.67 19873200 28.82 NaN
2000-01-07 148.00 151.88 147.00 151.31 20141400 29.94 NaN
2000-01-10 152.69 154.06 151.12 151.25 15226500 29.93 NaN
2000-01-11 151.00 152.69 150.62 151.50 15123000 29.98 NaN
2000-01-12 151.06 153.25 150.56 152.00 18342300 30.08 NaN
2000-01-13 153.13 154.94 153.00 153.75 14953500 30.42 1.0
2000-01-14 153.38 154.63 149.56 151.00 18480300 29.88 1.0
2000-01-18 149.62 149.62 146.75 148.00 18296700 29.29 NaN
2000-01-19 146.50 150.94 146.25 148.72 14849700 29.43 NaN
2000-01-20 149.06 149.75 142.63 145.94 30759000 28.88 1.0
2000-01-21 147.94 148.25 143.94 144.13 24005400 28.52 1.0
2000-01-24 145.31 145.94 136.44 138.13 27116100 27.33 1.0
2000-01-25 138.06 140.38 137.00 138.50 25387500 27.41 NaN
2000-01-26 140.50 142.19 138.88 141.44 15856800 27.99 NaN
2000-01-27 141.56 141.75 137.06 141.75 19243500 28.05 1.0
2000-01-28 140.31 140.50 133.63 134.00 29846700 26.52 1.0
2000-01-31 134.00 135.94 133.06 134.00 21782700 26.52 NaN
2000-02-01 134.25 137.00 134.00 136.00 27339000 26.91 NaN
Traceback (most recent call last):
File "C:\stocks\question4 for stack overflow.py", line 15, in <module>
jj = [ii[i] for i in range(1,len(ii)) if dd[i-1] > 2]
File "C:\stocks\question4 for stack overflow.py", line 15, in <listcomp>
jj = [ii[i] for i in range(1,len(ii)) if dd[i-1] > 2]
TypeError: Cannot cast ufunc greater input from dtype('<m8[ns]') to dtype('<m8') with casting rule 'same_kind'
我想要做的是将列'x'更改为连续三个1的集合,不重叠。所期望的输出是:
Open High Low Close Volume Adj Close x
Date
2000-01-03 153.00 153.69 149.19 150.00 22069800 29.68 1.0
2000-01-04 147.25 148.00 144.00 144.00 22121400 28.49 1.0
2000-01-05 143.75 147.00 142.56 143.75 27292800 28.44 1.0
2000-01-06 143.12 146.94 142.63 145.67 19873200 28.82 NaN
2000-01-07 148.00 151.88 147.00 151.31 20141400 29.94 NaN
2000-01-10 152.69 154.06 151.12 151.25 15226500 29.93 NaN
2000-01-11 151.00 152.69 150.62 151.50 15123000 29.98 NaN
2000-01-12 151.06 153.25 150.56 152.00 18342300 30.08 NaN
2000-01-13 153.13 154.94 153.00 153.75 14953500 30.42 1.0
2000-01-14 153.38 154.63 149.56 151.00 18480300 29.88 1.0
2000-01-18 149.62 149.62 146.75 148.00 18296700 29.29 1.0
2000-01-19 146.50 150.94 146.25 148.72 14849700 29.43 NaN
2000-01-20 149.06 149.75 142.63 145.94 30759000 28.88 1.0
2000-01-21 147.94 148.25 143.94 144.13 24005400 28.52 1.0
2000-01-24 145.31 145.94 136.44 138.13 27116100 27.33 1.0
2000-01-25 138.06 140.38 137.00 138.50 25387500 27.41 NaN
2000-01-26 140.50 142.19 138.88 141.44 15856800 27.99 NaN
2000-01-27 141.56 141.75 137.06 141.75 19243500 28.05 1.0
2000-01-28 140.31 140.50 133.63 134.00 29846700 26.52 1.0
2000-01-31 134.00 135.94 133.06 134.00 21782700 26.52 1.0
2000-02-01 134.25 137.00 134.00 136.00 27339000 26.91 NaN
所以,1月18日5,以及从NaN的〜1.0 31变化。
正如上面的评论所述,代码的第二部分适用于基于整数的索引。但是,在使用dtype datetime64 [ns]的日期时间索引时它不起作用。我想我只需要对代码的第二部分进行小小的调整就可以实现这一点(希望)。
由于提前, 大卫
--------------------------跟进部分------- -----------------------------
谢谢你和我一起挂在b2002。由于它的简洁性,我真的试图保持最佳的解决方案。当我运行代码开箱,这里是输出:
与
原始输出... JJ = [II对于i [i]于范围(1,LEN(ⅱ)),如果DD [I-1]> 2] ...
...一个[CI:CI + 2 = 1.0 ...
Open High Low Close Volume Adj Close x ii dd jj jj desired
Date
2000-01-03 153.00 153.69 149.19 150.00 22069800 29.68 1.0 1
2000-01-04 147.25 148.00 144.00 144.00 22121400 28.49 1.0 1
2000-01-05 143.75 147.00 142.56 143.75 27292800 28.44 1.0 2 x x
2000-01-06 143.12 146.94 142.63 145.67 19873200 28.82 1.0 3 1
2000-01-07 148.00 151.88 147.00 151.31 20141400 29.94 NaN 4 1
2000-01-10 152.69 154.06 151.12 151.25 15226500 29.93 NaN 5 1
2000-01-11 151.00 152.69 150.62 151.50 15123000 29.98 NaN 6 1
2000-01-12 151.06 153.25 150.56 152.00 18342300 30.08 NaN 7 1
2000-01-13 153.13 154.94 153.00 153.75 14953500 30.42 1.0 1
2000-01-14 153.38 154.63 149.56 151.00 18480300 29.88 1.0 1
2000-01-18 149.62 149.62 146.75 148.00 18296700 29.29 1.0 10 3 x x x
2000-01-19 146.50 150.94 146.25 148.72 14849700 29.43 1.0 11 1
2000-01-20 149.06 149.75 142.63 145.94 30759000 28.88 1.0 1
2000-01-21 147.94 148.25 143.94 144.13 24005400 28.52 1.0 1
2000-01-24 145.31 145.94 136.44 138.13 27116100 27.33 1.0 1
2000-01-25 138.06 140.38 137.00 138.50 25387500 27.41 1.0 15 4 z z
2000-01-26 140.50 142.19 138.88 141.44 15856800 27.99 1.0 16 1
2000-01-27 141.56 141.75 137.06 141.75 19243500 28.05 1.0 1
2000-01-28 140.31 140.50 133.63 134.00 29846700 26.52 1.0 1
2000-01-31 134.00 135.94 133.06 134.00 21782700 26.52 1.0 19 3 x x x
2000-02-01 134.25 137.00 134.00 136.00 27339000 26.91 1.0 20 1
我真的想了解是怎么回事,所以我在之前,之后和之后设置列ii,dd,jj。当我调整输入到:
... JJ = [II对于i [i]于范围(1,LEN(ⅱ)),如果DD [I-1]> 2] ...
...一个[CI:CI + 1] = 1.0 ...
这里是输出:
Open High Low Close Volume Adj Close x
Date
2000-01-03 153.00 153.69 149.19 150.00 22069800 29.45 1.0
2000-01-04 147.25 148.00 144.00 144.00 22121400 28.27 1.0
2000-01-05 143.75 147.00 142.56 143.75 27292800 28.22 1.0
2000-01-06 143.12 146.94 142.63 145.67 19873200 28.60 NaN
2000-01-07 148.00 151.88 147.00 151.31 20141400 29.70 NaN
2000-01-10 152.69 154.06 151.12 151.25 15226500 29.69 NaN
2000-01-11 151.00 152.69 150.62 151.50 15123000 29.74 NaN
2000-01-12 151.06 153.25 150.56 152.00 18342300 29.84 NaN
2000-01-13 153.13 154.94 153.00 153.75 14953500 30.18 1.0
2000-01-14 153.38 154.63 149.56 151.00 18480300 29.64 1.0
2000-01-18 149.62 149.62 146.75 148.00 18296700 29.05 1.0
2000-01-19 146.50 150.94 146.25 148.72 14849700 29.19 NaN
2000-01-20 149.06 149.75 142.63 145.94 30759000 28.65 1.0
2000-01-21 147.94 148.25 143.94 144.13 24005400 28.29 1.0
2000-01-24 145.31 145.94 136.44 138.13 27116100 27.12 1.0
2000-01-25 138.06 140.38 137.00 138.50 25387500 27.19 1.0
2000-01-26 140.50 142.19 138.88 141.44 15856800 27.77 NaN
2000-01-27 141.56 141.75 137.06 141.75 19243500 27.83 1.0
2000-01-28 140.31 140.50 133.63 134.00 29846700 26.31 1.0
2000-01-31 134.00 135.94 133.06 134.00 21782700 26.31 1.0
2000-02-01 134.25 137.00 134.00 136.00 27339000 26.70 NaN
唯一的问题是与1月25日,其中np.diff是给的值4.我只需要跳过4的值就可以保留现有的三个1。我试图它进入与这两个尝试没有工作就上www.jj-fashion.com JJ之前修改DD:
dd[dd == 4] = 1
dd = [3 if x==4 else x for x in dd]
也试图修改与此JJ条目:
JJ = [II [I]对于i在范围(1,LEN(ⅱ))如果((DD == 4)或([I-1]> 2))]
其给出此错误消息:
Traceback (most recent call last):
File "C:\stocks\question4 for stack overflow.py", line 109, in <module>
jj = [ii[i] for i in range(1,len(ii)) if ((dd == 4) or (dd[i-1] > 2))]
File "C:\stocks\question4 for stack overflow.py", line 109, in <listcomp>
jj = [ii[i] for i in range(1,len(ii)) if ((dd == 4) or (dd[i-1] > 2))]
ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()
人有有任何想法吗?
您可以尝试使用'ix'作为基于混合标签/基于整数的访问而不是'loc',或reset_index并执行转换并将set_index返回到日期 – Anzel
您可以解释代码的逻辑吗?你想做什么?为什么在这些行中需要连续3个1? – Parfait
冻糕 - 这只是一个例子。它背后没有具体的原因。 –