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我尝试使用iOS的JSONModel框架从我的自定义对象中创建JSON文件。我得到的错误:使用JSONModel序列化自定义对象
-[JSONModel.m:1077] EXCEPTION: Invalid type in JSON write (RegisterBuyerDataOption)
-[JSONModel.m:1077] EXCEPTION: Invalid type in JSON write (RegisterBuyerDataOption)
-[JSONModel.m:1077] EXCEPTION: Invalid type in JSON write (RegisterBuyerData)
registerBuyerData.h
@interface RegisterBuyerData : JSONModel
@property (nonatomic, strong) NSString *buyerDataID;
@property (nonatomic ) RegisterBuyerDataType type;
@property (nonatomic, strong) NSString<Optional> *title;
@property (nonatomic ) BOOL required;
@property (nonatomic, strong) NSString *value;
@property (nonatomic) NSNumber<Optional> *price;
@property (nonatomic) NSNumber<Optional> *availability;
@property (nonatomic, strong) NSArray<RegisterBuyerData*> *fields; //array of more RegisterBuyerData
@property (nonatomic, strong) NSArray<RegisterBuyerDataOption*> *options; //key,value array for dropDown
@property (nonatomic, strong) NSArray *parentValue;
@property (nonatomic, strong) NSArray<RegisterBuyerData*> *children; //array of more RegisterBuyerData but only for special selected value of an options field
- (BOOL) isAvailableForUser;
@end
registerBuyerData.m
@implementation RegisterBuyerData
- (BOOL) isAvailableForUser{
return (!_availability || [_availability integerValue] > 0);
}
+(JSONKeyMapper*)keyMapper
{
return [[JSONKeyMapper alloc] initWithDictionary:@{@"id": @"buyerDataID",@"value": @"value"}];
}
@end
RegisterBuyerDataOption.h
@interface RegisterBuyerDataOption : JSONModel
@property (nonatomic, strong) NSString *key;
@property (nonatomic, strong) NSString *value;
@property (nonatomic, strong) NSNumber *price;
@property (nonatomic, strong) NSNumber *availability;
- (BOOL) isAvailableForUser;
@end
是没可能创建一个JSON字符串递归?当我调用toJSONString方法时,我得到这些错误。
我试过,但Xcode中不想再建:类型参数 'RegisterBuyerData' 必须是指针(需要'*') – tuvok
@tuvok请参阅编辑。 –
thx,这是问题所在。我添加了@protocol RegisterBuyerData @end;并在没有指针的情况下将数组类型更改为NSArray。 –
tuvok