1
的y蜱标签鉴于以下数据帧:Matplotlib颜色经由环路
import pandas as pd
import numpy as np
df=pd.DataFrame({'A':['A','B','C','D','E','F','G','H','I','J','K','L','M','N'],
'B':[20,25,39,43,32,17,40, 40, 34, 56, 76, 23, 54, 34]})
我想创建气泡图,其中每个y-蜱标签是颜色作为其相应的点相同。下面的代码很好用,如果我只在我的颜色列表中说4行数据和4种颜色。但是,由于某些原因,当我有超过9行左右的数据(以及我的颜色列表中的颜色)时,它仅占用l.set_color(i)行中的前9个颜色元素。任何想法为什么会发生这种情况?迭代时它是否是zip的限制?与数据框相关?
import matplotlib.pyplot as plt
import matplotlib.ticker as mtick
labels=df.A[::-1]
vals=df.B[::-1]
ind=np.arange(len(labels))
colors1=['r','g','b','c','y','y','y','g','b','c','y','y','y','g']
fig, ax = plt.subplots(1, 1, figsize = (6,4))
for i in ind:
plt.plot(vals[i],i,marker='o',markeredgecolor='none', markersize=17, alpha=.5, linestyle='none', color=colors1[i])
ax.tick_params(axis='x',which='both',bottom='on',top='off',color='grey',labelcolor='grey')
ax.tick_params(axis='y',which='both',left='off',right='off',color='grey',labelcolor='grey')
ax.spines['top'].set_visible(False);ax.spines['right'].set_visible(False);
ax.spines['bottom'].set_visible(False);ax.spines['left'].set_visible(False)
ax.set_xlim([0,50])
ax.set_ylim([min(ind)-1,max(ind)+1])
fontcols=colors1[::-1]
for l,i in zip(ax.yaxis.get_ticklabels(),fontcols):
l.set_color(i)
l.set_fontsize(11)
print(l,i) #This shows that only 9 members are being colored for some reason
plt.yticks(ind,labels,fontsize=14)
plt.show()
提前感谢!
哇,谢谢之前扭转颜色列表!奇迹般有效。 –