我正在使用Arduino Mega 2560板实验室中的一个小型项目。我想对三角波的正斜率部分(上升)的信号(电压)进行平均,以尝试去除尽可能多的噪声。我的频率是20Hz,我正在使用115200比特/秒的数据速率(最快由Arduino推荐将数据传输到计算机)。如何使用Python对信号进行平均去除噪声
原始信号看起来像这样:
我的数据被存储在文本文件中,用对应于数据点的每一行。因为我确实有数千个数据点,所以我期望有些平均值可以使我的信号看起来很平滑,并在这种情况下形成一条近乎完美的直线。然而,其他实验条件可能会导致信号沿三角波的正斜率部分出现特征,例如负峰值,我绝对需要能够在平均信号上看到此特征。
我是一名Python初学者,所以我可能没有理想的方法来做到这一点,我的代码可能对大多数人看起来不好,但我仍然想获得关于如何改进我的信号处理代码的提示/想法通过平均信号来实现更好的噪声消除。
#!/usr/bin/python
import matplotlib.pyplot as plt
import math
# *** OPEN AND PLOT THE RAW DATA ***
data_filename = "My_File_Name"
filepath = "My_File_Path" + data_filename + ".txt"
# Open the Raw Data
with open(filepath, "r") as f:
rawdata = f.readlines()
# Remove the \n
rawdata = map(lambda s: s.strip(), rawdata)
# Plot the Raw Data
plt.plot(rawdata, 'r-')
plt.ylabel('Lightpower (V)')
plt.show()
# *** FIND THE LOCAL MAXIMUM AND MINIMUM
# Number of data points for each range
datarange = 15 # This number can be changed for better processing
max_i_range = int(math.floor(len(rawdata)/datarange))-3
#Declare an empty lists for the max and min
min_list = []
max_list = []
min_list_index = []
max_list_index = []
i=0
for i in range(0, max_i_range):
delimiter0 = i * datarange
delimiter1 = (i+1) * datarange
delimiter2 = (i+2) * datarange
delimiter3 = (i+3) * datarange
sumrange1 = sum(float(rawdata[i]) for i in range(delimiter0, delimiter1 + 1))
averagerange1 = sumrange1/len(rawdata[delimiter0:delimiter1])
sumrange2 = sum(float(rawdata[i]) for i in range(delimiter1, delimiter2 + 1))
averagerange2 = sumrange2/len(rawdata[delimiter1:delimiter2])
sumrange3 = sum(float(rawdata[i]) for i in range(delimiter2, delimiter3 + 1))
averagerange3 = sumrange3/len(rawdata[delimiter2:delimiter3])
# Find if there is a minimum in range 2
if ((averagerange1 > averagerange2) and (averagerange2 < averagerange3)):
min_list.append(min(rawdata[delimiter1:delimiter2])) # Find the value of all the minimum
#Find the index of the minimum
min_index = delimiter1 + [k for k, j in enumerate(rawdata[delimiter1:delimiter2]) if j == min(rawdata[delimiter1:delimiter2])][0] # [0] To use the first index out of the possible values
min_list_index.append(min_index)
# Find if there is a maximum in range 2
if ((averagerange1 < averagerange2) and (averagerange2 > averagerange3)):
max_list.append(max(rawdata[delimiter1:delimiter2])) # Find the value of all the maximum
#Find the index of the maximum
max_index = delimiter1 + [k for k, j in enumerate(rawdata[delimiter1:delimiter2]) if j == max(rawdata[delimiter1:delimiter2])][0] # [0] To use the first index out of the possible values
max_list_index.append(max_index)
# *** PROCESS EACH RISE PATTERN ***
# One rise pattern goes from a min to a max
numb_of_rise_pattern = 50 # This number can be increased or lowered. This will average 50 rise patterns
max_min_diff_total = 0
for i in range(0, numb_of_rise_pattern):
max_min_diff_total = max_min_diff_total + (max_list_index[i]-min_list_index[i])
# Find the average number of points for each rise pattern
max_min_diff_avg = abs(max_min_diff_total/numb_of_rise_pattern)
# Find the average values for each of the rise pattern
avg_position_value_list = []
for i in range(0, max_min_diff_avg):
sum_position_value = 0
for j in range(0, numb_of_rise_pattern):
sum_position_value = sum_position_value + float(rawdata[ min_list_index[j] + i ])
avg_position_value = sum_position_value/numb_of_rise_pattern
avg_position_value_list.append(avg_position_value)
#Plot the Processed Signal
plt.plot(avg_position_value_list, 'r-')
plt.title(data_filename)
plt.ylabel('Lightpower (V)')
plt.show()
最后,处理后的信号看起来是这样的:
我希望更直的线,但我可能是错的。我相信我的代码中可能存在很多缺陷,并且肯定会有更好的方法来实现我想要的。如果你们中的任何一个人想要获得它的乐趣,我已经包含了带有一些原始数据的文本文件的链接。
http://www108.zippyshare.com/v/2iba0XMD/file.html
这可能会更好codereview.stackexchange.com –
谢谢,我刚刚开始在那里的一个线程,但如果有人想在这里帮助,你是欢迎。 – LaGuille
我将不胜感激,如果你可以看看这个:https://stackoverflow.com/questions/44458859/python-finding-pattern-in-a-lot –