所以我有一个给出输出的代码,我需要做的是在逗号之间拉出信息,将它们分配给一个变量,当被调用时动态变化。 ..这里是我的代码:如何从Python中的输出中提取特定信息
import re
data_directory = 'Z:/Blender_Roto/'
data_file = 'diving_board.shape4ae'
fullpath = data_directory + data_file
print("====init=====")
file = open(fullpath)
for line in file:
current_line = line
# massive room for optimized code here.
# this assumes the last element of the line containing the words
# "Units Per Second" is the number we are looking for.
# this is a non float number, generally.
if current_line.find("Units Per Second") != -1:
fps = line_split = float(current_line.split()[-1])
print("Frames Per Second:", fps)
# source dimensions
if current_line.find("Source Width") != -1:
source_width = line_split = int(current_line.split()[-1])
print("Source Width:", source_width)
if current_line.find("Source Height") != -1:
source_height = line_split = int(current_line.split()[-1])
print("Source Height:", source_height)
# aspect ratios
if current_line.find("Source Pixel Aspect Ratio") != -1:
source_px_aspect = line_split = int(current_line.split()[-1])
print("Source Pixel Aspect Ratio:", source_px_aspect)
if current_line.find("Comp Pixel Aspect Ratio") != -1:
comp_aspect = line_split = int(current_line.split()[-1])
print("Comp Pixel Aspect Ratio:", comp_aspect)
# assumption, ae file can contain multiple mocha shapes.
# without knowing the exact format i will limit the script
# to deal with one mocha shape being animated N frames.
# this gathers the shape details, and frame number but does not
# include error checking yet.
if current_line.find("XSpline") != -1:
# record the frame number.
frame = re.search("\s*(\d*)\s*XSpline", current_line)
if frame.group(1) != None:
frame = frame.group(1)
print("frame:", frame)
# pick part the part of the line that deals with geometry
match = re.search("XSpline\((.+)\)\n", current_line)
line_to_strip = match.group(1)
points = re.findall('(\(.*?\))', line_to_strip)
print(len(points))
for point in points:
print(point)
print("="*40)
file.close()
这使我的输出:
====init=====
Frames Per Second: 24.0
Source Width: 2048
Source Height: 778
Source Pixel Aspect Ratio: 1
Comp Pixel Aspect Ratio: 1
frame: 20
5
(0.793803,0.136326,0,0.5,0)
(0.772345,0.642332,0,0.5,0)
(0.6436,0.597615,0,0.5,0)
(0.70082,0.143387,0,0.5,0.25)
(0.70082,0.112791,0,0.5,0)
========================================
所以我需要的例子是能够分配(0.793803,0.136326,0,0.5,0)到(1x,1y,1z,1w,1s),(0.772345,0.642332,0,0.5,0)到(2x,2y,2z,2w,2s)等等,这样无论填入那些p他们将承担这个价值。
这里是我需要把这些数字为代码:
#-------------------------------------------------------------------------------
# Name: Mocha Rotoscoping Via Blender
# Purpose: Make rotoscoping more efficient
#
# Author: Jeff Owens
#
# Created: 11/07/2011
# Copyright: (c) jeff.owens 2011
# Licence: Grasshorse
#-------------------------------------------------------------------------------
#!/usr/bin/env python
import sys
import os
import parser
sys.path.append('Z:\_protomotion\Prog\HelperScripts')
import GetDir
sys.path.append('Z:\_tutorials\01\tut01_001\prod\Blender_Test')
filename = 'diving_board.shape4ae'
infile = 'Z:\_tutorials\01\tut01_001\prod\Blender_Test'
import bpy
from mathutils import Vector
#below are taken from mocha export
x_width =2048
y_height = 778
z_depth = 0
frame = 20
def readText():
text_file = open('diving_board.shape4ae', 'r')
lines = text_file.readlines()
print (lines)
print (len.lines)
for line in lines:
print (line)
##sets points final x,y,z value taken from mocha export for blender interface
point1x = (0.642706 * x_width)
point1y = (0.597615 * y_height)
point1z = (0 * z_depth)
point2x = (0.770557 * x_width)
point2y = (0.647039 * y_height)
point2z = (0 * z_depth)
point3x = (0.794697 * x_width)
point3y = (0.0869024 * y_height)
point3z = (0 * z_depth)
point4x = (0.707973* x_width)
point4y = (0.0751348 * y_height)
point4z = (0 * z_depth)
w = 1 # weight
listOfVectors = [Vector((point1x,point1y,point1z)),Vector((point2x,point2y,point2z)),Vector((point3x,point3 y,point3z)),Vector((point4x,point4y,point4z)), Vector((point1x,point1y,point1z))]
def MakePolyLine(objname, curvename, cList):
curvedata = bpy.data.curves.new(name=curvename, type='CURVE')
curvedata.dimensions = '3D'
objectdata = bpy.data.objects.new(objname, curvedata)
objectdata.location = (0,0,0) #object origin
bpy.context.scene.objects.link(objectdata)
polyline = curvedata.splines.new('POLY')
polyline.points.add(len(cList)-1)
for num in range(len(cList)):
x, y, z = cList[num]
polyline.points[num].co = (x, y, z, w)
MakePolyLine("NameOfMyCurveObject", "NameOfMyCurve", listOfVectors)
那么,我有我的载体,我想能够把(PX,PY,0.z,PW,PS)然后(p2.x,p2.y,p2.zp2.wp2.s)等,以便它可以改变每个给定的数字
任何帮助将是伟大的..先谢谢你!
-Jeff
解析Python中的文本其实很简单,但你必须自己想出一个方法。从头开始,我会在新行上分割字符串(使用[str.split](http://docs.python.org/library/stdtypes.html#str.split))来解决这个问题,然后解析每条线分别使用组合str.split和简单检查。只要文本的格式没有改变,你就可以为这个特定的情况编写解析器。 –