2015-05-27 174 views
1

我是Java新手。我试图使用下式来计算三角形的面积:计算三角形的面积

S =(侧1 +侧2 +侧3)/ 2

面积=平方根(侧( - 侧)(侧 - side2)(side - side3)

如果用户输入三点: 1.5 -3.4 4.6 5 9.5 -3.4那么三角形的面积应该是33.6但是,我的程序运行,但它给我不正确的答案,下面是我的代码

// Import Java Scanner 
import java.util.Scanner; 
import java.lang.Math; 
public class Ex_2_19 { 
    public static void main(String[] args) { 
    //Create a Scanner object 
    Scanner input = new Scanner(System.in); 
    float side = 0; 
    float area1 = 0; 
    float area2 = 0; 
    float area3 = 0; 
    float area4 = 0; 
    float calculatedarea = 0; 

    //Prompt the user to enter three points of a triangle 
    System.out.println("Enter point x1:"); 
    System.out.println("Enter point y1:"); 
    System.out.println("Enter point x2:"); 
    System.out.println("Enter point y2:"); 
    System.out.println("Enter point x3:"); 
    System.out.println("Enter point y3:"); 

    //Define the variables 
    float Pointx1 = input.nextFloat(); 
    float Pointy1 = input.nextFloat(); 
    float Pointx2 = input.nextFloat(); 
    float Pointy2 = input.nextFloat(); 
    float Pointx3 = input.nextFloat(); 
    float Pointy3 = input.nextFloat(); 

    //Formula to calculate the area of a triangle 
    side = (Pointx1 + Pointy1 + Pointx2 + Pointy2 + Pointx3 + Pointy3)/2; 
    area1 = side - (Pointx1 + Pointy1); 
    area2 = side - (Pointx2 + Pointy2); 
    area3 = side - (Pointx3 + Pointy3); 
    area4 = side * area1 * (area2) * (area3); 
    calculatedarea = (float) (Math.sqrt(area4)); 
    //calculatedarea = (float) (Math.sqrt(area1)*(area2) * (area3)); 

    //Print result 
    System.out.println("The area of the triangle is " + calculatedarea); 


} 

}

+2

您正在使用的公式适用于三角形边的长度。你只是将每个点的X和Y坐标加起来 - 与长度无关。 –

+0

基于https://www.mathsisfun.com/geometry/herons-formula.html,通过计算每对xy坐标之间的距离来查找长度a,b,c。你计算区域1,2,3,4的方式似乎是错误的。 – Gosu

回答

4

您正在尝试Heron's Formula - 注意abc是点之间的欧氏距离,因此需要由sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2))计算等的差异而不仅仅是总和。