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我使用Visual Studio 2010开始有点用C#旋转2D对象C#
方案有3个文本框和一个按钮,旋转2D点我得到这些的textBox coordenadaX,coordenadaY和角度需要计算和显示新的2D点有以下代码:
private void button1_Click(object sender, EventArgs e)
{
float x = float.Parse(textX.Text);
float Y = float.Parse(textY.Text);
double angulo = float.Parse(textAng.Text);
rotate(x, Y, angulo);
}
private void rotate(float cordX, float cordY, double angle)
{
double s = Math.Sin(angle);
double c = Math.Cos(angle);
double newX = cordX * c - cordY * s;
double newY = cordX * s + cordY * c;
lblResult.Text = ("" + newX + " : " + "" + newY);
}
}
例如用户报告:coordenadaX = 10,coordenadaY = 10,角= 180的正确答案将是新的2D点: - 10:-10