从csv文件使用matplotlib和pandas绘制直方图

Question

我的csv文件非常复杂..它包含数字以及字符串属性。 这是我的CSV文件看起来像 我要绘制的过程柱状图对比的CPUID

Answer 1

您可以通过hist使用read_csv，indexing with str和情节：

import pandas as pd 
import matplotlib.pyplot as plt 
import io 

temp=u"""kmem_kmalloc;{cpu_id=1} 
kmem_kmalloc;{cpu_id=1} 
kmem_kmalloc;{cpu_id=1} 
kmem_kmalloc;{cpu_id=1} 
kmem_kfree;{cpu_id=1} 
kmem_kfree;{cpu_id=1} 
power_cpu_idle;{cpu_id=0} 
power_cpu_idle;{cpu_id=0} 
power_cpu_idle;{cpu_id=3}""" 

s = pd.read_csv(io.StringIO(temp), #after testing replace io.StringIO(temp) to filename 
       sep=";", #set separator, if sep=',' can be omited (default sep = ,) 
       header=None, #no header in csv 
       names=[None,'cpuid'], #set names of columns, (first is None because index) 
       index_col=0, #first column set to index 
       squeeze=True) #try convert DataFrame to Series 
print s 
kmem_kmalloc  {cpu_id=1} 
kmem_kmalloc  {cpu_id=1} 
kmem_kmalloc  {cpu_id=1} 
kmem_kmalloc  {cpu_id=1} 
kmem_kfree  {cpu_id=1} 
kmem_kfree  {cpu_id=1} 
power_cpu_idle {cpu_id=0} 
power_cpu_idle {cpu_id=0} 
power_cpu_idle {cpu_id=3} 
Name: cpuid, dtype: object 

#if max cpu <= 9, use Indexing with .str 
s = s.str[-2].astype(int) 

#if cpu > 9 
#s= s.str.extract('(\d)', expand=False) 
print s 
kmem_kmalloc  1 
kmem_kmalloc  1 
kmem_kmalloc  1 
kmem_kmalloc  1 
kmem_kfree  1 
kmem_kfree  1 
power_cpu_idle 0 
power_cpu_idle 0 
power_cpu_idle 3 
Name: cpuid, dtype: int32 

plt.figure(); 
s.hist(alpha=0.5) 
plt.show()