public class TestMatrica {
public static void main(String[] args) {
double matrica[][] = new double[2][2];
inputElements(matrica);
printElements(matrica);
}
private static void inputElements(double m[][])
{
Scanner in = new Scanner(System.in);
for (int i = 0; i < m.length; i++)
{
for (int j = 0; j < m[0].length; j++)
{
System.out.println("Unesite element na poziciji [" + i + ", " + j + "]: ");
m[i][j] = Double.parseDouble(in.nextLine()); /////////// }
}
in.close();
好吧,所以我的问题是什么(in.nextLine());在m [i] [j] = Double.parseDouble(in.nextLine());做m [i] [j] = Double.parseDouble(in.nextLine())是做什么的?
您应该养成阅读[Java API文档](https://docs.oracle.com/javase/8/docs/api/)的习惯。寻找“Double”和“Scanner”类(这是你的“in”类型),并找到那里的方法。 – RealSkeptic