使用在熊猫系列

Question

我有一个熊猫系列在他们。我话的集合列出一串的数量出现想找到一个特定的词的频率在每个列表对于例如， 该系列产品是

0 [All, of, my, kids, have, cried, nonstop, when... 
1 [We, wanted, to, get, something, to, keep, tra... 
2 [My, daughter, had, her, 1st, baby, over, a, y... 
3 [One, of, babys, first, and, favorite, books, ... 
4 [Very, cute, interactive, book, My, son, loves... 

我想要得到每行孩子的数量。我曾尝试

series.count('kids') 

这给了我一个错误说“级别的孩子必须是相同的名称（无）”

series.str.count('kids) 

给我NaN值。

我应该如何去获取计数？

Answer 1

使用

In [5288]: series.apply(lambda x: x.count('kids')) 
Out[5288]: 
0 1 
1 0 
2 0 
3 0 
4 0 
Name: s, dtype: int64 

---

详细

In [5292]: series 
Out[5292]: 
0 [All, of, my, kids, have, cried, nonstop, when] 
1 [We, wanted, to, get, something, to, keep, tra] 
2 [My, daughter, had, her, 1st, baby, over, a, y] 
3  [One, of, babys, first, and, favorite, books] 
4 [Very, cute, interactive, book, My, son, loves] 
Name: s, dtype: object 

In [5293]: type(series) 
Out[5293]: pandas.core.series.Series 

In [5294]: type(series[0]) 
Out[5294]: list 

Answer 2

在原系列，使用str.findall + str.len：

print(series) 

0  All of my kids have cried nonstop when 
1  We wanted to get something to keep tra 
2  My daughter had her 1st baby over a y 
3  One of babys first and favorite books 
4 Very cute interactive book My son loves 

print(series.str.findall(r'\bkids\b')) 

0 [kids] 
1  [] 
2  [] 
3  [] 
4  [] 
dtype: object 

counts = series.str.findall(r'\bkids\b').str.len() 
print(counts) 

0 1 
1 0 
2 0 
3 0 
4 0 
dtype: int64