的继this文章中,我想了解如何与lineiterator工作使用。我写了下面的代码:试图了解Lineiterator
#include <opencv2/core/core.hpp>
#include <opencv2/highgui/highgui.hpp>
#include <iostream>
using namespace cv;
using namespace std;
int main()
{
Mat img = imread("C:\\Users\\Acme\\Desktop\\image-processing\\2.bmp");
LineIterator it(img, 1, 200, 8);
LineIterator it2 = it;
vector<Vec3b> buf(it.count);
for(int i = 0; i < it.count; i++, ++it)
{
buf[i] = *(const Vec3b)*it;
printf("%d\n", buf[i]);
}
return 0;
}
但它给错误:
Error 1 error C2664: 'cv::LineIterator::LineIterator(const cv::Mat &,cv::Point,cv::Point,int,bool)' : cannot convert parameter 2 from 'int' to 'cv::Point' c:\users\acme\documents\visual studio 2010\projects\iterator\opencv1\helloworld.cpp 15
Error 2 error C2100: illegal indirection c:\users\acme\documents\visual studio 2010\projects\iterator\opencv1\helloworld.cpp 22
3 IntelliSense: no instance of constructor "cv::LineIterator::LineIterator" matches the argument list c:\users\acme\documents\visual studio 2010\projects\iterator\opencv1\helloworld.cpp 15
4 IntelliSense: no operator "*" matches these operands c:\users\acme\documents\visual studio 2010\projects\iterator\opencv1\helloworld.cpp 22
我期待的是BUF将打印存储我跨线的值。有人能帮助我理解如何纠正这个问题吗?
尝试'LineIterator it(img,cv :: Point(startX,startY),cv :: Point(endX,endY),8);'而不是。看看这个例子:http://docs.opencv.org/modules/core/doc/drawing_functions.html#lineiterator – Micka
@Micka这给错误C2100:buf [i] = *(const Vec3b非法间接寻址)*它;这也给智能感知:无操作“*” – gpuguy
看一下例子链接匹配这些操作数。解引用不会给你颜色值,而是像素位置。您必须手动从图像中读取它们的值! – Micka