Seaborn调色板 - 防止颜色回收

Question

Seaborn允许定义包含多种颜色的调色板，适用于多行图表。但是，当将调色板设置为多种颜色时，只会使用前六种颜色，之后颜色将循环使用，从而难以区分线条。这可以通过显式调用调色板来覆盖，但这不方便。有没有办法强制Seaborn电流调色板不要回收颜色，当超过6个定义？

实施例：

from matplotlib import pyplot as plt 
import pandas as pd 
import seaborn as sb 

# Define a palette with 8 colors 
cmap = sb.blend_palette(["firebrick", "palegreen"], 8) 
sb.palplot(cmap) 

# Set the current palette to this; only 6 colors are used 
sb.set_palette(cmap) 
sb.palplot(sb.color_palette()) 

df = pd.DataFrame({x:[x*10, x*10+5, x*10+10] for x in range(8)}) 
fig, (ax1, ax2) = plt.subplots(2,1,figsize=(4,6)) 
# Using the current palette, colors repeat 
df.plot(ax=ax1) 
ax1.legend(bbox_to_anchor=(1.2, 1)) 
# using the palette that defined the current palette, colors don't repeat 
df.plot(ax=ax2, color=cmap) 
ax2.legend(bbox_to_anchor=(1.2, 1)) ; 

Answer 1

溶液（T汉克斯@tcaswell的指针）：设置调色板显式地使用所有的颜色：

# Setting the palette using defaults only finds 6 colors 
sb.set_palette(cmap) 
sb.palplot(sb.color_palette()) 
sb.palplot(sb.color_palette(n_colors=8)) 

# but setting the number of colors explicitly allows it to use them all 
sb.set_palette(cmap, n_colors=8) 
# Even though unless you explicitly request all the colors it only shows 6 
sb.palplot(sb.color_palette()) 
sb.palplot(sb.color_palette(n_colors=8)) 

# In a chart, the palette now has access to all 8 
fig, ax1 = plt.subplots(1,1,figsize=(4,3)) 
df.plot(ax=ax1) 
ax1.legend(bbox_to_anchor=(1.2, 1)) ;