绘制三角形

Question

进出口试图以允许用户绘制三角形形状。我得到的起点和终点，用公式找到一个等边三角形的第三点形成三角形，但似乎并不奏效任何想法我怎么能做到这一点？也许使用一个圈子，但我不知道如何去做。这是我目前的代码。

NSValue *point = [_path objectAtIndex:0]; 
CGPoint startPoint = point.CGPointValue; 

point = [_path lastObject]; 
CGPoint endPoint = point.CGPointValue; 

CGPoint thirdPoint = CGPointMake(((startPoint.x+endPoint.x)/2), (((startPoint.x-endPoint.x)/2)*(tan(60))+1)); 
UIBezierPath *triangle = [UIBezierPath bezierPath]; 
[triangle moveToPoint:startPoint]; 
[triangle addLineToPoint:endPoint]; 
[triangle addLineToPoint:thirdPoint]; 
[triangle addLineToPoint:startPoint]; 
triangle.lineWidth=size; 

Answer 1

这应该计算等边三角形的第三点：

CGPoint startPoint = ..., endPoint = ...; 

CGFloat angle = M_PI/3; // 60 degrees in radians 
// v1 = vector from startPoint to endPoint: 
CGPoint v1 = CGPointMake(endPoint.x - startPoint.x, endPoint.y - startPoint.y); 
// v2 = v1 rotated by 60 degrees: 
CGPoint v2 = CGPointMake(cosf(angle) * v1.x - sinf(angle) * v1.y, 
         sinf(angle) * v1.x + cosf(angle) * v1.y); 
// thirdPoint = startPoint + v2: 
CGPoint thirdPoint = CGPointMake(startPoint.x + v2.x, startPoint.y + v2.y); 

UIBezierPath *triangle = [UIBezierPath bezierPath]; 
[triangle moveToPoint:startPoint]; 
[triangle addLineToPoint:endPoint]; 
[triangle addLineToPoint:thirdPoint]; 
[triangle closePath]; 
// ...