如果函数失败,我想退出脚本。通常情况下这不是问题,但如果使用工艺替代,则会成为问题。Bash退出和进程替换
$ cat test.sh
#!/bin/bash
foo(){
[ "$1" ] && echo pass || exit
}
read < <(foo 123)
read < <(foo)
echo 'SHOULD NOT SEE THIS'
$ ./test.sh
SHOULD NOT SEE THIS
基于CodeGnome’s answer这似乎工作
$ cat test.sh
#!/bin/bash
foo(){
[ "$1" ] && echo pass || exit
}
read < <(foo 123) || exit
echo 'SHOULD SEE THIS'
read < <(foo) || exit
echo 'SHOULD NOT SEE THIS'
$ ./test.sh
SHOULD SEE THIS
提示:您的foo构建不会评估您的想法。正如所写,您的foo函数将始终返回true。你可能希望foo包含'{test -n“$ 1”&& echo pass; } ||退出1'。 – 2012-07-24 00:50:25