2016-02-05 83 views
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我有一个背景纹理和透明图层纹理。 当我只加载这些纹理时_layer3最终纹理处于活动状态。多活动纹理opengl

我希望所有的纹理都应该处于活动状态,以便我知道图层要进一步处理。

glActiveTexture(GL_TEXTURE0); 
    glBindTexture(GL_TEXTURE_2D, texture[0]);//texture _floorTexture 
    glUniform1i(_textureUniform, 0); 
      //glUniform1i(glPrograms[currentProgram].glUniforms[_textureUniform],_floorTexture); 

    glActiveTexture(GL_TEXTURE0 + 1); 
    glBindTexture(GL_TEXTURE_2D, texture[1]); //_layer0 
    glUniform1i(_textureUniform, 1); 

    glActiveTexture(GL_TEXTURE0 + 2); 
    glBindTexture(GL_TEXTURE_2D, texture[2]); //_layer1 
    glUniform1i(_textureUniform, 2); 

    glActiveTexture(GL_TEXTURE0 + 3); 
    glBindTexture(GL_TEXTURE_2D, texture[3]); //_layer2 
    glUniform1i(_textureUniform, 3); 

    glActiveTexture(GL_TEXTURE0 + 4); 
    glBindTexture(GL_TEXTURE_2D, texture[4]); //_layer3 
    glUniform1i(_textureUniform, 4); 
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当你想使用多重纹理,你还需要在着色器的多个采样,并结合他们的结果。 Atm,你会在每次纹理绑定之后覆盖制服的绑定。 – BDL

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嗨,你可以分享多个纹理的示例着色器吗? – SathiyaKrishnan

回答

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当使用多个纹理时,还必须在着色器中使用多个采样器。这可能看起来像这样:

in vec2 uv; 

out vec3 color; 

uniform sampler2D floor_texture; 
uniform sampler2D layer0_texture; 

void main() 
{ 
    vec4 f = texture(floor_texture, uv); 
    vec4 l0 = texture(layer0_texture, uv); 

    color = mix(f.rgb, l0.rgb, 1 - l0.a); 
} 

请注意,组成取决于你想达到什么,这只是一个例子。

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感谢您的代码。立即尝试并回复你.. – SathiyaKrishnan

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它显示灰色屏幕。 – SathiyaKrishnan

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你是否正在设置两个采样器制服?当你用0或1替换混合的第三个参数时会发生什么? – BDL

-2

这是我的着色器

precision highp float; 
varying vec2 interpolatedTextureCoordinate; 
uniform sampler2D sourceTexture; 
uniform float amount; 
uniform sampler2D layerTexture; 
const float PI = 3.14159265358979323846264; 
const vec4 backgroundColor = vec4(0.0, 0.0, 0.0, 1.0); 
const vec2 center = vec2(0.5, 0.5); 
void main() 
{ 
vec4 source = texture2D(sourceTexture, interpolatedTextureCoordinate); 
vec4 layer0 = texture2D(layerTexture, interpolatedTextureCoordinate); 
float sigma = amount; 
float distance = distance(center, interpolatedTextureCoordinate); 
loat alpha = 2.0 * (1.0/sqrt(2.0 * PI)) * exp((-sigma) * pow(distance, 2.0)); 
gl_FragColor = mix(source.rgb, layer0.rgb , 1-layer0.a); 

} 

问候 Sathiya